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A 12 V DC to 0–30 V DC, 5 A supply is not a simple linear-regulator schematic.
The correct solution is a high-power switching converter, preferably:
Key points:
A practical engineering answer is therefore:
Below is a practical text schematic for a single-stage non-inverting synchronous buck-boost supply.
+12V INPUT
|
F1 20A
|
Reverse polarity
protection MOSFET
|
TVS diode
|
+-------+-----------------------------+
| |
CIN1..CINn |
(low-ESR electrolytic + ceramic) |
| |
GND |
|
Q1 Q3
+---MOSFET-----MOSFET---+
| | | |
| SW1 SW2 |
| +----L1----+ |
| |
| |
+---MOSFET-----MOSFET-+
Q2 Q4
| |
GND GND
U1 = 4-switch buck-boost controller
drives Q1..Q4
|
+---------------------> +VOUT
|
COUT1..COUTn
(50V low-ESR caps)
|
GND
+VOUT ---- R1 ----+---- R2 ---- GND
|
FB ---> U2A error amplifier ---> U1 feedback pin
Output current shunt:
LOAD- ---- RSHUNT ---- GND
Voltage across RSHUNT ---> U2B current limit amplifier ---> U1 current/COMP clamp
Voltage set potentiometer ---> U2A reference
Current set potentiometer ---> U2B reference
+5V auxiliary ---- charge pump inverter ---- -2V rail
-2V rail powers U2A/U2B so the control loop can regulate all the way to 0V.
Without that small negative rail, many controllers can regulate down only to about 0.5–1.0 V, not true zero.
These are engineering-grade example values, not final production values.
| Block | Suggested value / class |
|---|---|
| Input fuse | 20 A |
| Input capacitors | 2,000–3,000 µF total low-ESR + 10 µF + 100 nF ceramics |
| MOSFETs Q1–Q4 | 80 V N-channel, low \(R_{DS(on)}\), low gate charge |
| Inductor L1 | 10–15 µH, saturation current > 25 A, low DCR |
| Output capacitors | 1,000–1,500 µF total, 50 V low-ESR + ceramic bypass |
| Output shunt | 10 mΩ, Kelvin-connected, 3–5 W |
| Switching frequency | 150–300 kHz typical |
| Auxiliary rail | +5 V and about -2 V for control op-amp |
| Controller family | LM5175 / LM5176 / LTC3780 / LT8390 class |
This requirement has three separate engineering difficulties.
You want:
That means the converter must do both:
So:
This is why the first offline answer, which proposed a simple boost stage, is incomplete for a true 0–30 V output.
Maximum output power is:
\[ P{out} = V{out} \times I_{out} = 30 \times 5 = 150\text{ W} \]
If efficiency is 90%:
\[ P_{in} = \frac{150}{0.9} \approx 167\text{ W} \]
At 12 V input:
\[ I_{in} = \frac{167}{12} \approx 13.9\text{ A} \]
In practice, design for:
If the source is a battery and input falls to 11 V:
\[ I_{in} = \frac{167}{11} \approx 15.2\text{ A} \]
So your:
must all be sized for this current.
This is the most important correction to the simplistic “12 V in, 30 V 5 A out” idea:
it is feasible only if the 12 V source can provide very high current.
Many DC-DC controllers regulate to an internal reference such as:
That means the lowest direct output is usually not 0 V.
If you need a real laboratory-style 0.00 V to 30.00 V, you typically need one of these methods:
Use a charge pump or auxiliary winding to generate about -1.5 V to -3 V for the error amplifier.
Advantages:
Disadvantages:
The converter regulates from about 0.8 V upward, and a MOSFET disconnects output for “0 V”.
Advantages:
Disadvantages:
Switching pre-regulator plus linear pass stage.
Advantages:
Disadvantages:
For your requirement, Method A is the best engineering solution.
A lot of “0–30 V 5 A” schematics use:
That works only when the raw DC bus is already higher than 30 V, usually derived from mains AC.
It does not solve:
So if you start from 12 V DC, you need switch-mode conversion.
| Topology | Can do 0–30 V from 12 V? | Complexity | Efficiency | Recommendation |
|---|---|---|---|---|
| Linear regulator only | No | Low | Very poor | Not suitable |
| Boost only | No, not below 12 V | Medium | Good | Incomplete |
| Buck only | No, not above 12 V | Medium | Good | Incomplete |
| Boost + buck | Yes | High | Good | Very practical |
| 4-switch buck-boost | Yes | High | Very good | Best single-stage |
If you are designing from scratch:
For easiest implementation: use 2-stage
For best final design: use single-stage 4-switch synchronous buck-boost
In current power electronics practice, the preferred approach for this power range is:
Current design trends emphasize:
For a 150 W design, discrete legacy controllers such as TL494/SG3525 can still be used, but they are usually more difficult to stabilize and optimize than a modern dedicated buck-boost controller.
It uses two half-bridges and one inductor:
Operating modes:
When \(V{out} < V{in}\)
When \(V{out} > V{in}\)
When \(V{out} \approx V{in}\)
This gives continuous regulation across the whole range.
Do not use marginal MOSFETs such as 55 V parts in a 30 V output boost/buck-boost design unless you have carefully verified transients.
A safer engineering choice is typically:
because switching spikes and ringing can easily exceed the nominal bus voltage.
At 150 W output, the inductor does not just carry 5 A.
In boost or buck-boost operation, inductor average current is much closer to the input-side power current, so it may be:
Therefore choose:
For a 5 A output limit, a practical low-side shunt is:
\[ R_{shunt} = 0.01\ \Omega \]
At 5 A:
\[ V_{shunt} = 5 \times 0.01 = 50\text{ mV} \]
Power in shunt:
\[ P = I^2R = 25 \times 0.01 = 0.25\text{ W} \]
Still choose 3–5 W physical rating for robustness, lower temperature rise, and pulse tolerance.
Use Kelvin connections to the shunt.
Do not sense current through heavy copper traces.
For electronics engineering, the main issues here are safety, compliance, and reliability rather than ethics in the abstract.
If this will be sold or used in commercial equipment, consider:
At 150 W, poor layout or undersized parts can overheat:
If you want the highest chance of success:
12V IN --> synchronous boost to 36V --> synchronous buck CC/CV to 0-30V / 5A
Why this is easier:
Use if:
These are critical.
Especially:
For 15–20 A class current:
Use:
Join them at a single controlled point near the controller sense reference.
For:
Provide RC or RCD snubbers if ringing appears on switching nodes.
Bring it up in this order:
So a “complete final schematic” requires choosing the exact controller first.
If you continue this design, the most valuable next topics are:
A good next engineering step is to decide between:
Then the schematic can be finalized around one controller family.
Your specification is feasible, but only under the right conditions:
If you want, I can next give you one of these in a full pin-by-pin schematic:
User question
from an existing 230v transformer to produce a 0-30v dc, 5A power supply with CC and CV schematic pdf . This is an upgrade to an old psu.
Artificial Intelligence Response
Direct answer to the question
Yes, you can upgrade an old transformer PSU to 0–30 V DC, 5 A, with constant-voltage and constant-current control, but it is only practical if your existing transformer secondary is roughly 28–30 VAC at 6–8 A. If it is only 24 VAC, you will usually not get a reliable 30 V at 5 A with a linear regulator.
For a classic low-noise bench supply, the most suitable retrofit is:
This is consistent with the intended use of the LM723: TI specifies that it is a series regulator, adjustable from 2 V to 37 V, supports external pass transistors for currents beyond 10 A, and includes current-limit/foldback application examples in the official datasheet. (ti.com)
Important correction: a plain LM723 circuit does not naturally give true 0 V output, because its normal output range is 2–37 V. For a real 0–30 V supply, add a small negative control rail (for example −5 V) or accept that the minimum output may sit a little above zero. (ti.com)
I cannot attach a binary PDF directly in chat, but I can give you a PDF-ready schematic below that you can copy into KiCad/EasyEDA or print to PDF.
Detailed problem analysis
1) Feasibility of your existing transformer
For a linear 0–30 V / 5 A supply, the raw DC after rectification must remain above the regulated output at full load:
[ V{RAW(min)} \approx V{OUT(max)} + V{dropout} + V{ripple} ]
For a practical linear stage:
So you want roughly:
[ V_{RAW(min)} \approx 35\text{ to }37\text{ V} ]
That means the transformer should usually be:
Quick rule:
2) Why the thermal design is the real challenge
At low output voltages, a linear PSU burns most of the power in the pass transistors:
[ P{pass}=(V{RAW}-V{OUT})\cdot I{OUT} ]
Example at 5 V / 5 A with about 38 V raw DC:
[ P_{pass}=(38-5)\cdot 5=165\text{ W} ]
That is a very large continuous heat load. This is why many professional bench supplies use:
If you do not add tap switching, the supply can still work, but 0–10 V at 5 A becomes a severe thermal case.
3) Why LM723 + CA3140 is still a good retrofit choice
The LM723 remains a valid classical choice for a retrofit because it was designed for series regulators, supports an external pass transistor, and TI’s official datasheet includes both external NPN pass and current-limit/foldback example topologies. (ti.com)
The CA3140 is useful for the current loop because it can run from 4 V to 36 V supply and its input common-mode range can go 0.5 V below the negative rail, which is helpful when sensing low-value shunts near ground or slightly below it in a retrofit PSU. (renesas.com)
The 2N3055 is still usable in this type of build, but you must respect its 60 V VCEO, 15 A collector current, 115 W dissipation at case = 25°C, and especially its safe operating area/second-breakdown limits. That is why one transistor is not enough for a reliable 5 A bench supply; use at least 3, preferably 4, plus emitter ballast resistors. (onsemi.com)
4) Recommended topology for your upgrade
I recommend this architecture:
This gives a proper lab-style CV/CC crossover:
Current information and trends
The traditional LM723 approach is still technically valid, and TI still documents it as usable in linear or switching regulator roles with external pass devices. (ti.com)
Current design practice, however, tends to prefer one of these for 0–30 V / 5 A:
For an old PSU upgrade, a linear retrofit still makes sense if you want:
But if you want continuous low-voltage/high-current use, a hybrid preregulator is the better modern direction.
Supporting explanations and details
Recommended PDF-ready schematic
A. Power input and rectifier
B. Output/pass stage
C. Driver stage
D. Current shunt
At 5 A:
[ V_{RS}=I\cdot R=5\cdot 0.1=0.5\text{ V} ]
[ P_{RS}=I^2R=25\cdot 0.1=2.5\text{ W} ]
So use a 10 W resistor for margin.
E. Control supply
Without the −5 V rail, expect the minimum output to be slightly above zero.
F. CV loop using LM723
Use the LM723 in the same external NPN pass transistor style as TI’s official application circuit, but with your BD139/2N3055 pass bank. TI’s datasheet explicitly shows that operating mode. (ti.com)
G. CC loop using CA3140
Operation:
CTRL_NODE.QL1.QL1pullsCTRL_NODEdown, reducing BD139 drive and forcing constant current.H. Protection and finishing parts
This scheme uses the LM723 exactly where it is strongest—precision CV control with external pass devices—and uses the CA3140 as a clean adjustable CC clamp, which fits its single-supply/high-input-impedance characteristics. (ti.com)
Ethical and legal aspects
Also note that an old PSU chassis may have:
Check those before reusing it.
Practical guidelines
Minimum BOM
Heatsink guidance
For serious use:
Calibration procedure
Dummy load examples
For rough testing:
Possible disclaimers or additional notes
Suggestions for further research
If you want to improve this design further, consider:
Also, the best official PDF references for the control core are:
Brief summary
Your upgrade is feasible if the transformer secondary is about 28–30 VAC at 6–8 A.
The best classical retrofit is:
If you want, in the next message I can convert this into one of these two formats:
If you send your transformer secondary details, for example:
24 VAC 6 A28 VAC 8 A2 x 15 VACI can finalize the values for your exact transformer.