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Calculating Capacitor Impedance for Resistor Replacement in a Circuit

myncio 31176 13
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Treść została przetłumaczona polish » english Zobacz oryginalną wersję tematu
  • #1 1285174
    myncio
    Level 12  
    how to calculate the impedance of a capacitor, my point is to replace the resistor
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  • Helpful post
    #2 1285456
    12robert12
    Level 29  
    I think the formula for high school capacitance is enough:

    Quote:
    $$Xc = \frac{1}{2 \pi f C}$$




    of course this is a theoretical capacitor, you have to add the internal resistance and take into account that capacitors may behave differently at different frequencies.

    greetings :D
  • Helpful post
    #3 1286633
    eedy
    Level 15  
    if it is to be a real capacitor, the internal resistance should be taken into account and the impedance formula is Z = ? (R? + Xc? ;) where R is the internal resistance and Xc is the capacitor reactance
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  • #4 1286693
    myncio
    Level 12  
    and how to calculate r2
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    #5 1286851
    jozefg
    VIP Meritorious for electroda.pl
    myncio wrote:
    and how to calculate r2
    I would not like to be malicious - but in math lessons you must have slept ...
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    #6 1287048
    eedy
    Level 15  
    as for R, you can calculate them from the formulas for Xc (he was higher) Uc = I * Xc Ur = I * RU = I * Z U? = Uc? + Ur? and Z (also above)
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    #7 1287092
    RSP
    Level 27  
    Gentlemen, why are you scaring a man. If this capacitor is to operate at low frequencies and, additionally, its reactance tolerance may exceed 10%, the first formula is sufficient. The rest of the parameters are of little importance.
  • #8 1287571
    myncio
    Level 12  
    ok, but how to calculate the internal resistance
    like Z I don't have what pattern
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    #9 1287579
    RSP
    Level 27  
    Do you need to calculate all the real parameters of a capacitor ie apart from capacitance, resistance, inductance, and various other junk. Write what you need it for, because maybe your calculations are pointless.
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  • #10 1287659
    myncio
    Level 12  
    I would like to replace all resistors - conden in the system but I found out that you need to calculate the impedances and I ask?
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    #11 1287733
    RSP
    Level 27  
    What is this deal.
  • #12 1287771
    myncio
    Level 12  
    For example, to regulate the rotation of commutar motors, let's say replace resistors - with capacitors
    exactly that instead of resistors, give capacitors in any system
    or build a circuit on capacitors
  • Helpful post
    #13 1287778
    ~sojer
    Level 27  
    myncio wrote:
    I would like to replace all resistors - condenium in the system but I found out that you need to calculate the impedances and I ask?


    how can you ??? I guess I slept in lessons too :oops:
  • Helpful post
    #14 1287801
    RSP
    Level 27  
    If capacitors could be inserted everywhere instead of resistors, the production of resistors would probably be abandoned. Capacitors are used instead of resistors in only one case. When a high-value alternating current flows through the resistor and the voltage drop across the resistor is significant, significant power is emitted across the resistor. Such a resistor can be replaced with a capacitor, provided that we do not mind the current and voltage shift introduced by this capacitor. We gain only that there are no power losses in the capacitor (of course, I ignore the negligible losses caused by the imperfection of the capacitor). To calculate the capacitor, the colleague's formula 12robert12 is enough.

Topic summary

The discussion revolves around calculating the impedance of a capacitor to potentially replace resistors in a circuit. Participants emphasize the importance of considering internal resistance and reactance when determining impedance, with the formula Z = √(R² + Xc²) being suggested. Some responses indicate that for low-frequency applications, a simpler approach may suffice. The conversation also touches on the practicality of replacing resistors with capacitors, noting that this is only feasible under specific conditions, such as when managing significant power losses in resistors. The need for precise calculations is highlighted, particularly in applications like motor control.
Summary generated by the language model.
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