Powering 1m 5050 LED Strip with 10000mAh Power Bank: Converting Voltage & Managing Output

Question

Hello all. As I did not find anything on this topic in the forum I created a new topic. I am asking for some hints if someone comes to mind how to solve my problem because I personally lack ideas. 1. The problem is that I need to power the LED strip mounted on the portable device. It is not...

krzysiek_krm · Accepted Answer

Hello, I assume that these parameters apply to the entire roll, so in your case the current will be at 1.2 A. I understand that the power bank has a typical output voltage of 5 V. If this converter had 100% efficiency, the output current would be 1.2 A * (12 V / 5 V) = 2.88 A, the converter does not have 100% efficiency, the input current will be much higher . It is surprising that your inverter works at all, according to the description, it has the maximum current entrance equal to 1.4 A. You can use a step up converter At 12 V output voltage and 1.2 A current, you will achieve efficiency of around 88%, i.e. 5 V power consumption will be equal to (12 V * 1.2 A) / 88% = 16.36 W, loss power will be 16.36 W - 14.4 W = 1.96 W, maybe some radiator should be used on the inverter. greetings

Wojciech. · Accepted Answer

You can simply connect 3 cells in series and you will have 11-13V, but charging is troublesome. Use this XL6009 inverter.

Jackziom · Accepted Answer

Hello!

Unfortunately, but I do not see that you can get a voltage of 12V from the device. Given the costly and sensible use of a converter that will increase the voltage twice and give quite a lot of power I would give up this idea. It will be much simpler and cheaper according to the idea of colleague "Wojciech." buy 3 links or buy a ready-made package.

Obtaining such cells can be obtained quite easily, from power tools - then (usually) they have not substantial capacities, but high possible continuous discharge current of up to 20A, or from used laptop batteries.
Of course, slightly more reliable (in terms of actual capacity) and probably slightly more expensive will be buying new cells or buying a ready-made package - preferably with protection.

There is also the option of buying links and a basket with security - this design has many advantages - easy replacement of links, quick assembly and disassembly of links, possibility of charging the link in an external charger.

Opting out of the inverter has the advantage that it greatly simplifies the structure and also the losses that in such operating conditions are inevitable and since the structure is powered from cells, the efficiency of the whole is important here.

krzysiek_krm · Accepted Answer

It is difficult to say, maybe it is compatible with any version of Quick Charge, according to this standard the charging voltage can be even greater than 12 V. However, the USB device must negotiate the appropriate power supply / charging parameters, the LED strip will not do that. Theoretically, you can slightly modify the tape. The description shows that the current of one diode is 20 mA. You can try to replace the serial diode resistors on the tape with current sources, for example From documentation it follows that the source is working properly with a minimum bias voltage of 2.5 V, after adding the forward diode voltage, the total voltage will be greater than 5 V from the power bank. However, you can use a step up converter with an output voltage of about 6 V, the input current will be on average twice as low as for the 12 V output voltage, power loss on the tape will be much lower, the efficiency of the entire system will increase. The diagram in Figure 15 of the mentioned documentation shows that the starting voltage of the current source is slightly higher than 1.5 V, you could try to test the converted tape with 5 V test.

Hipolek · Answer

Thank you for your interest in my topic.

I have a power bank from the following link:
http://allegro.pl/power-bank-benks-usb-c-3-0-...gle&utm_medium=cpc&ev_campaign=plasklep-benks

1. The specification says that it can give a voltage of 12V. However, nowhere did I find information on how to get such tension from it.

Hipolek · Answer

In that case, I give up the power bank.

I had the idea to use a modeling cell or a basket for batteries (or rechargeable batteries) 12v.

What do you say??
What parameters should such a link have for enough for about 2 hours of continuous lighting.
The gel battery that I mentioned this 4.5 Ah withstood about 10 hours of continuous operation.

Wojciech. · Answer

You know the power consumption of the tape, then you can easily calculate the capacity.

vicio_32 · Answer

Hello.
I found an interesting solution.
I just converted the power supply.
Instead of batteries, I used a power bank with a capacity of 4,000 mAh.
With this configuration I got the effect of 9 hours of ordination without a break.

Anonymous · Answer

He replaced a colleague with a 4.5Ah gel battery for a 4Ah lithium-ion battery. Was it not better to improve the power supply from the gel battery? A colleague has a charger for it, so you would end up buying a converter to power the belt.
Independent construction of a battery with a poor basket and miserable chargers is also a dull idea and additionally expensive.

Powering 1m 5050 LED Strip with 10000mAh Power Bank: Converting Voltage & Managing Output

Post #1

Post #2

Post #3

Post #4

Post #5

Post #6

Post #7

Post #8

Post #9

Post #10

Didn't find an answer? Ask Artificial Intelligence

Topic summary