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Calculating the bulb power for 12V knowing the parameters for 24V

marekkgb 12927 15
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  • #1 16855577
    marekkgb
    Level 11  
    Hello all. I am a mechanic, car diagnostician.
    I have a question about the 12V tester. The point is that there is a 24V 3W bulb inside. My question is: How do I calculate (using the formula) the power of this bulb for a voltage of 12V?
    For example, to match and buy a bulb for 12V and .... W.
    I am asking for this because I measured the current consumption of this bulb for a voltage of 12.5 V.
    It was 0.065A. The formula for the power P = U × I shows that this bulb has only 0.8W.
    Thank you for your help

    Added after 2 [minutes]:

    Calculating the bulb power for 12V knowing the parameters for 24V Calculating the bulb power for 12V knowing the parameters for 24V
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    #2 16855635
    Ture11
    Level 39  
    marekkgb wrote:
    The formula for the power P = U × I shows that this bulb has only 0.8W.

    The most appropriate pattern. At 12 volts you should have 1.5 W. As for the reason why you get these results - I would bet that the cable with the alligator clip has a lot of resistance.
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    #3 16855639
    Anonymous
    Level 1  
  • Helpful post
    #4 16855669
    Jawi_P
    Level 36  
    Buy a normal 12V 250mA or 3W tubular bulb, there are plenty of them on the net.
    Although when it comes to the sampler itself, why replace the bulb? This one is so universal that, as you have experienced for yourself, it lights at 12 and at 24V.
  • Helpful post
    #5 16855695
    jack63
    Level 43  
    These calculations suck. Bulbs have a resistance strongly dependent on temperature, i.e. in consequence of the flowing current. Moreover, this correlation is non-linear.
    Measure the resistance of the bulb with an ohmmeter, you will be surprised ...
    Attention eurotips as the most appropriate!
    Anyway, who is sensible in the 21st century uses a signal finder light bulb ???
  • #6 16855780
    marekkgb
    Level 11  
    First of all, thank you all for your prompt reply.
    Buddy Jawi_P
    with the current current flowing through the tester I will not do any harm to the ECU. However, 0.2 A will surely close each relay coil.
    My friend Ture11
    I can measure the resistance of the bulb itself and the wire without load. But since the current flows through the non-load resistance will be close to zero. Currently, the resistances in automotive installations are rarely measured. I focus on the voltage, voltage drops and voltage type.
    Buddy jack63- what's the deal with using a light bulb as a signal finder - if you can ask?
    I use a 21W bulb to check the circuits under load. Moreover, if I am not satisfied with the result, I can always measure the voltage drop under the load of this bulb on each element of this circuit.

    Continuing with the main question how to convert 24V 3W to 12V. Such an example:
    ,, The customer comes to me with the above-mentioned bulb - I tell him that they are no longer available (or horrendously expensive). How am I supposed to choose a 12V bulb for him?

    Thanks
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    #7 16856644
    Freddy
    Level 43  
    marekkgb wrote:
    ,, The customer comes to me with the above-mentioned bulb - I tell him that they are no longer available (or horrendously expensive). How am I supposed to choose a 12V bulb for him?
    Why do you want to lie to the customer, such bulbs are available without any problem and cost about PLN 3.
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  • #8 16856666
    Adamcyn
    Level 38  
    marekkgb wrote:
    How to calculate (using formula) the power of this bulb for 12V?

    marekkgb wrote:
    I measured the current consumption of this bulb for a voltage of 12.5 V.
    It was 0.065A. The formula for the power P = U × I shows that this bulb has only 0.8W.

    Your calculations are correct.
    For 12.0 volts, use the same method.

    Using the formula instead of measuring will be more difficult because:
    jack63 wrote:
    Bulbs have a resistance strongly dependent on temperature, i.e. in consequence of the flowing current. Moreover, this correlation is non-linear.
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  • #9 16856766
    marekkgb
    Level 11  
    Thanks Adamcyn

    I understand the non-linearity of resistance. But I mean, no one on the forum will answer the following question.

    Calculate how much electricity is consumed by a 24W 3W bulb connected to a 12V voltage source?

    After all, I should probably remember that I will not mention schools, not studies.

    For me, this question is very simple, but I have a problem with the answer.
    best regards

    Added after 6 [minutes]:

    Buddy Freedy
    It was a hypothetical query. I have already ordered this bulb - even a few. And it's about my 12V tester.
    How to calculate theoretically the equivalent of 24V 3W.
  • Helpful post
    #10 16856792
    Adamcyn
    Level 38  
    marekkgb wrote:
    For me, this question is very simple, but I have a problem with the answer.

    Then read what the famous outlaw, excellent electronics engineer - a colleague wrote on a similar subject Quarz:
    Quarz wrote:
    Hello,
    arturbaka wrote:
    Calculate the intensity of the current flowing through the light bulb with the power p = 100 Watt with the voltage u = 220 Volt
    a) what is the resistance of this bulb
    b) what will change the power dissipated on this light bulb if we connect it to the voltage u = 110 Volt
    The question in point b) was composed by a man with very poor practical knowledge, not to say - a dilettante electrician ...
    A tungsten filament bulb (and show me with another ...) is a nonlinear DC resistor with all the consequences that come with it.
    Therefore, one cannot construct the content of the task basing it on the constant value of the resistance of the bulb's fiber determined at its rated parameters, and then using this value of the resistance of the fiber at the voltage supplying this bulb by half as much.
    YOU MUST NOT DO THIS! !! !!
    This is for several reasons;
    1. Numerical values that are completely inconsistent with reality are determined.
    2. This activity "makes brain water" into young minds by teaching them bad habits.
    3. The untrue knowledge persisted in the minds of the learners.
    This shows a complete lack of imagination by the person arranging such a task.

    This task - correctly - can only be solved by using the current-voltage characteristic removed from this bulb.
    The above-mentioned characteristic can be obtained by supplying the bulb with a steeply increasing DC voltage (or measuring the RMS voltage, but with such a frequency value that during the forcing period there is no change in the fiber temperature) and measuring the current value - at individual points - when the equilibrium occurs heat between this bulb and its surroundings.
    And when you already have the above-mentioned characteristics, finding the parameters you are looking for does not pose any problems ...

    arturbaka wrote:
    data:
    P = 100 watts
    U1 = 220volt
    u2 = 110 volts
    The presentation of units of electric quantities 'cries out to heaven' ...

    I will give myself a comment on the calculations presented here.

    best regards


    https://www.elektroda.pl/rtvforum/topic1021995.html#postingbox
  • #11 16856824
    marekkgb
    Level 11  
    Buddy Adamcyn. I am completely satisfied with your answer.
    I understand and thank you.

    Added after 6 [minutes]:

    It's still such a small question.
    Will every current collector or circuit component follow the same principle as you quoted?
  • Helpful post
    #12 16856865
    Adamcyn
    Level 38  
    marekkgb wrote:
    Will every current collector or circuit component follow the same principle as you quoted?

    This is quite a complex topic and it starts with the distinction between DC or AC voltage.
  • Helpful post
    #13 16856884
    krzysiek_krm
    Level 40  
    Hello,
    marekkgb wrote:
    Calculate how much electricity is consumed by a 24W 3W bulb connected to a 12V voltage source?

    If the light bulb had a constant resistance (which is of course not true because its resistance depends on the temperature), the current intensity would be twice lower. Simply Ohm's law: I = V / R. As for the power, P = V * I = V ^ 2 / R = I ^ 2 * R, so the electric power for a constant resistance is proportional to square voltage or square current. This is called the Joule-Lenz law in physics. You decreased the voltage twice, the power decreased four times, approximately, of course, without taking into account the change in resistance.

    best regards
  • #14 16857073
    marekkgb
    Level 11  
    And that also explained a lot, my friend Krzysk. Thank you for your help. Marek
  • #16 16857748
    marekkgb
    Level 11  
    Yes. thanks to everyone I close the topic

Topic summary

The discussion revolves around calculating the power of a 24V 3W bulb when used in a 12V system. The main question posed by a mechanic involves determining the equivalent power for a 12V bulb based on measurements taken from the 24V bulb. Responses highlight that the power at 12V should be approximately 1.5W, although actual measurements showed only 0.8W due to the bulb's resistance being affected by temperature. Participants emphasize the non-linear relationship between voltage, current, and resistance, suggesting that the power decreases significantly when voltage is halved. Recommendations include purchasing a standard 12V bulb, as the original bulb is still available on the market. The conversation also touches on the use of light bulbs as signal finders in automotive diagnostics.
Summary generated by the language model.
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