How to Interface 12V Sensor Output to 3.3V Opamp in Differential Amplifier Configuration

Hi,
I have a sensor which is connected to +12V and it shows some small variations at the output.
I have an opamp which I have configured in AC input, inverting amplifier. therefore I should supply it with the load voltage and then find the best value for + rail (by default the half of the VCC which is 6), something like the figure below, but the opamp maximum supply is 3.3V. I am bounded to use this opamp and I can not change the sensor voltage.
<img src="http://uupload.ir/files/rqyc_design1.gif">

is there any method to fix this problem?
the input sensor circuit is something like this which is +12V referenced, not the ground referenced

<img  src="http://uupload.ir/files/ezex_2019-04-11_14-47-43.jpg">

Hi Hessam-Since the input to the OP amp is AC coupled and DC blocked, all you have to do is use a 3.3 volt regulator off of the 12 volt source to  get the proper voltage for the op amp.Some things to watch out for:
(1) . Make sure the voltage regulator you choose will accept 12 volts at the input.  Many of the 3.3 volt regulators have a lower limit.  Look at SPX3819M5-L-3-3
(2) If you use a polarized capacitor at the input of the OP amp make sure it is turned the correc t way.  If possible, use a ceramic capacitor so polarization is not important.
(3) Make sure the peak value of the signal  from the sensor doesn't spike the inputs of the OP amp when the circuit gets powered up.  It looks like D1 and D2 in your second circuit will take care of this.-Rick