Hello :) The question seems simple, but I'm not sure, so I'm curious about the answer ... it's about converting the flow (air stream) m3 / h to m / s ... This is needed to select a windmill :) - that's a hint ...

It is impossible to calculate, how do you want to change the volume to length? One would have to know the cross-sectional area of the tunnel in which this air flows

Hello m3 / h is the t unit of flow rate (Qv), and Qv = S * V, where S conduit section [m2], V - air velocity [m / s] after transformations: V = Qv / S [m / s] so much that Qv must be in m3 / s m3 / h to m3 / s, you probably already know how to convert? :) Regards

Exactly ... I agree ... so for this information I need the area of the windmill (square meters), then I will have the air flow speed (because m3 / h is the windmill efficiency - that's how I understand it, am / s air flow speed forced by a windmill with a given area) ...

How to convert airflow from m³/h to m/s for wind turbine selection?

Report a violation of the law

Reply | New topic

#1 641055 14 May 2004 16:06

mito mito

Level 11

Posts: 24

Rate: 7
» | Topic author

Post #1
641055 14 May 2004 16:06

Hello The question seems simple, but I'm not sure, so I'm curious about the answer ... it's about converting the flow (air stream) m3 / h to m / s ... This is needed to select a windmill - that's a hint ...
ADVERTISEMENT
#2 641060 14 May 2004 16:17

Gorgoroth Gorgoroth

VIP Meritorious for electroda.pl

Posts: 1852

Help: 28

Rate: 61
» | Helpful post? (0)

Post #2
641060 14 May 2004 16:17

It is impossible to calculate, how do you want to change the volume to length? One would have to know the cross-sectional area of the tunnel in which this air flows
ADVERTISEMENT
#3 641072 14 May 2004 16:27

sokmarcin sokmarcin

Level 20

Posts: 460

Help: 7

Rate: 235
» | Positive voted Helpful post? (+10)

Post #3
641072 14 May 2004 16:27

Hello
m3 / h is the t unit of flow rate (Qv), and Qv = S * V, where S conduit section [m2], V - air velocity [m / s]
after transformations: V = Qv / S [m / s] so much that Qv must be in m3 / s
m3 / h to m3 / s, you probably already know how to convert? :)

Regards
#4 641075 14 May 2004 16:28

mito mito

Level 11

Posts: 24

Rate: 7
» | Topic author Positive voted Helpful post? (+7)

Post #4
641075 14 May 2004 16:28

Exactly ... I agree ... so for this information I need the area of the windmill (square meters), then I will have the air flow speed (because m3 / h is the windmill efficiency - that's how I understand it, am / s air flow speed forced by a windmill with a given area) ...
Create an account, log in here. You will receive points by participating in discussions.
Join this discussion.

Install Elektroda application

Didn't find an answer? Ask Artificial Intelligence

*I agree to send the question to OpenAI, Anthropic PBC, Perplexity AI, Inc., Kagi Inc., Google LLC - owners of language models in order to prepare the best response. The companies may monitor and log information entered into the form.

*I agree to publicly display my question and answer. The question and answer will be publicly available to everyone. The process may take a few minutes. Upon completion, you will be redirected to the page with the answer.

Wait...(2min)

Reply | New topic

Report a violation of the law

How to convert airflow from m³/h to m/s for wind turbine selection?

Didn't find an answer? Ask Artificial Intelligence