logo elektroda
logo elektroda
X
logo elektroda

Schematics.com and Partsim.com shut down - Welcome to Elektroda

gulson 265476 105
  • #32 20663702
    simonhradsky
    Level 1  
    S tím že se jedná pouze to co jsem ještě
  • #33 20663705
    monoahmed335
    Level 4  
    @ElektrodaBot How to read resistor color code?
  • #34 20663709
    ElektrodaBot
    AI OpenAI ChatGPT4
    monoahmed335 wrote:
    How to read resistor color code?
    Resistor color codes are read using a specific chart. The color bands represent numbers and multipliers that, when combined, give you the resistance value of the resistor. The bands are read from left to right. Here's a quick guide:

    1. Black: 0
    2. Brown: 1
    3. Red: 2
    4. Orange: 3
    5. Yellow: 4
    6. Green: 5
    7. Blue: 6
    8. Violet: 7
    9. Gray: 8
    10. White: 9
    11. Gold: ±5% (tolerance)
    12. Silver: ±10% (tolerance)

    For a four-band resistor:
    - The first band represents the first digit.
    - The second band represents the second digit.
    - The third band is the multiplier (or the number of zeros to add).
    - The fourth band is the tolerance (accuracy) of the resistor.

    For example, if the bands are red (2), violet (7), brown (1, meaning 10^1 or 10), and gold (±5%), the resistor value is: 270 Ohms, with a tolerance of ±5%.

    Does that help in understanding how to read resistor color codes? Do you have a specific resistor that you're trying to read?
    You can call me in any topic by writing @ElektrodaBot. Disclaimer: Some answers provided by the ElektrodaBot may be inaccurate. Elektroda not responsible for accuracy, reliability or completeness of the information presented. All ElektrodaBot responses should be verified by the user. OpenAI can monitor and save information entered after calling ElektrodaBot.
  • #35 20671119
    ahmadri3711
    Level 1  
    1. Lichtschalter: Ausschaltung für das Licht in der Küche.
    2. Zwei Steckdosen: Eine befindet sich unterhalb des Lichtschalters, die andere ist frei im Raum platziert.
    3. Zusätzliche Steckdose für die Dunstabzugshaube: Diese Steckdose erhält nur Spannung, wenn der Fensterschalter dies freigibt, um sicherzustellen, dass der Abzug nur bei geöffnetem Fenster läuft.
    4. RCD (Residual Current Device): Ein gemeinsamer RCD für die beiden Steckdosenschaltungen, um Personen vor Stromschlägen zu schützen. Ein separater RCD schützt den Lichtstromkreis.
    5. Separate Herdanschlussdose: Mit 5x 2,5mm² Leitungen abgesichert, da der Herd aufgrund seines niedrigen Isolationswiderstands nicht über einen RCD geschützt werden kann. @ElektrodaBot

    Added after 3 [minutes]:

    1. Lichtschalter: Ausschaltung für das Licht in der Küche.
    2. Zwei Steckdosen: Eine befindet sich unterhalb des Lichtschalters, die andere ist frei im Raum platziert.
    3. Zusätzliche Steckdose für die Dunstabzugshaube: Diese Steckdose erhält nur Spannung, wenn der Fensterschalter dies freigibt, um sicherzustellen, dass der Abzug nur bei geöffnetem Fenster läuft.
    4. RCD (Residual Current Device): Ein gemeinsamer RCD für die beiden Steckdosenschaltungen, um Personen vor Stromschlägen zu schützen. Ein separater RCD schützt den Lichtstromkreis.
    5. Separate Herdanschlussdose: Mit 5x 2,5mm² Leitungen abgesichert, da der Herd aufgrund seines niedrigen Isolationswiderstands nicht über einen RCD geschützt werden kann. @ElektrodaBot
  • #36 20671130
    ElektrodaBot
    AI OpenAI ChatGPT4
    ahmadri3711 wrote:
    (...) RCD für die beiden Steckdosenschaltungen, um Personen vor Stromschlägen zu schützen. Ein separater RCD schützt den Lichtstromkreis.
    5. Separate Herdanschlussdose: Mit 5x 2,5mm² Leitungen abgesichert, da der Herd aufgrund seines niedrigen Isolationswiderstands nicht über einen RCD geschützt werden kann.
    Ihr Plan klingt sehr überlegt und durchdacht. Es ist wichtig, die Sicherheit in der Küche zu gewährleisten, insbesondere in Bezug auf Elektrizität. Ich habe allerdings ein paar Rückfragen, um Ihre Situation besser zu verstehen:

    1. Haben Sie vor, die Installation selbst durchzuführen oder planen Sie, einen Fachmann zu beauftragen?
    2. Wenn Sie planen, die Installation selbst durchzuführen, haben Sie bereits Erfahrung mit Elektroinstallationen?
    3. Haben Sie die notwendigen Werkzeuge und Materialien zur Verfügung?
    4. Sind die Leitungen für den Herd und die Dunstabzugshaube bereits vorhanden oder müssen diese noch verlegt werden?
    5. Planen Sie, zusätzliche Sicherheitsmaßnahmen wie Fehlerstrom-Schutzschalter (FI-Schalter) oder Leitungsschutzschalter (LS-Schalter) zu installieren?

    Ihre Antworten helfen mir, Sie besser zu beraten und sicherzustellen, dass Sie die besten und sichersten Lösungen für Ihre Küche bekommen.
    You can call me in any topic by writing @ElektrodaBot. Disclaimer: Some answers provided by the ElektrodaBot may be inaccurate. Elektroda not responsible for accuracy, reliability or completeness of the information presented. All ElektrodaBot responses should be verified by the user. OpenAI can monitor and save information entered after calling ElektrodaBot.
  • #37 20682764
    roshanchaudhari191
    Level 1  
    leraing

    Added after 54 [seconds]:

    .
  • #38 20694562
    khunakornnet7
    Level 1  
    Code: Powershell
    Log in, to see the code
  • #43 20765312
    elenogrech
    Level 1  
    Hi, I am looking for a schematic diagram for the power supply of Vivitek H1185HD home projector.
    Thanks,
    Eleno.
  • #45 20787324
    monoahmed335
    Level 4  
    @ElektrodaBot what java programming language best For AI?
    Explain advantages java prog language on theAI level?
  • #46 20787325
    ElektrodaBot
    AI OpenAI ChatGPT4
    monoahmed335 wrote:
    what java programming language best For AI?
    Explain advantages java prog language on theAI level?
    Java is indeed a good choice for Artificial Intelligence (AI) development due to several reasons:

    1. Platform Independence: Java programs can run on any device that has a Java Virtual Machine (JVM). This makes Java extremely portable and a great choice for developing AI applications that need to work across multiple platforms.

    2. Built-in Garbage Collection: This feature automatically frees up memory that isn't being used, which is a valuable asset when dealing with intensive AI tasks that can consume a lot of memory.

    3. Multi-threading Capability: Java supports multithreading, which is very useful in AI. It allows the simultaneous execution of two or more parts of a program for maximum utilization of CPU.

    4. Large Standard Library: Java provides a standard library that supports powerful mathematical operations, which can be useful in creating AI algorithms.

    5. Strong Community Support: Java has a large and active community of developers. This means that there are plenty of resources, libraries, and APIs available, making it a good choice for AI programming.

    6. Mature AI Libraries And Frameworks: Java provides several sophisticated, mature, and powerful AI-specific libraries and frameworks, such as WEKA, DL4J, Apache Jena, and more.

    However, keep in mind that the best programming language for AI largely depends on the specific requirements of the project, your team's expertise, and other factors. Python, for example, is also a very popular language for AI and Machine Learning due to its simplicity and the availability of relevant libraries.

    Do you have any specific AI project in mind you want to use Java for?
    You can call me in any topic by writing @ElektrodaBot. Disclaimer: Some answers provided by the ElektrodaBot may be inaccurate. Elektroda not responsible for accuracy, reliability or completeness of the information presented. All ElektrodaBot responses should be verified by the user. OpenAI can monitor and save information entered after calling ElektrodaBot.
  • #49 20810694
    ElektrodaBot
    AI OpenAI ChatGPT4
    darshanpatil6016 wrote:
    [/youtube]
    It seems like you might be trying to share or reference a YouTube video. However, your message only includes the tag [/youtube] without the video link or ID. If you'd like to discuss a specific video or topic related to electronics engineering, please provide me with the video link or the details of the content you're interested in discussing.

    I'm here to help with your questions or discussions related to electronics engineering!
    You can call me in any topic by writing @ElektrodaBot. Disclaimer: Some answers provided by the ElektrodaBot may be inaccurate. Elektroda not responsible for accuracy, reliability or completeness of the information presented. All ElektrodaBot responses should be verified by the user. OpenAI can monitor and save information entered after calling ElektrodaBot.
  • #50 20813597
    marcelfabiopereira
    Level 1  
    @ElektrodaBot
  • #52 20823859
    jakubkruza
    Level 1  
    @ElektrodaBot jak spočítat proudy v obvodu resustroů
  • #53 20823860
    ElektrodaBot
    AI OpenAI ChatGPT4
    jakubkruza wrote:
    jak spočítat proudy v obvodu resustroů
    Pro výpočet proudů v obvodu s rezistory potřebujeme vědět, jak jsou rezistory zapojeny – zda jsou ve série, paralelně, nebo v kombinaci obojího. Základní pravidla pro sériové a paralelní zapojení rezistorů jsou následující:

    1. Sériové zapojení:
    - Celkový odpor (Rt) je součtem jednotlivých odporů: $$Rt = R1 + R2 + \cdots + Rn$$.
    - Proud procházející sériovým obvodem je stejný pro všechny komponenty: $$I_{total} = I1 = I2 = \cdots = In$$.
    - Napětí se rozdělí mezi rezistory v poměru k jejich odporům.

    2. Paralelní zapojení:
    - Inverzní hodnota celkového odporu (1/Rt) je součtem inverzních hodnot odporů jednotlivých rezistorů: $$1/Rt = 1/R1 + 1/R2 + \cdots + 1/Rn$$.
    - Napětí na všech rezistorech v paralelním zapojení je stejné: $$V_{total} = V1 = V2 = \cdots = Vn$$.
    - Proud se rozdělí mezi paralelně zapojené rezistory v poměru inverzních hodnot jejich odporů.

    Pokud máte obvod s kombinací sériově a paralelně zapojených rezistorů, postupujete krok za krokem a redukujete složitější obvod na jednodušší, dokud nedosáhnete jednoho ekvivalentního odporu. Poté použijete Ohmův zákon ($$V = IR$$), kde $$V$$ je napětí, $$I$$ je proud a $$R$$ je odpor, pro výpočet neznámých hodnot.

    Můžete mi poskytnout konkrétní schéma nebo hodnoty rezistorů ve vašem obvodu? Díky tomu vám budu moci lépe poradit s výpočty proudů.
    You can call me in any topic by writing @ElektrodaBot. Disclaimer: Some answers provided by the ElektrodaBot may be inaccurate. Elektroda not responsible for accuracy, reliability or completeness of the information presented. All ElektrodaBot responses should be verified by the user. OpenAI can monitor and save information entered after calling ElektrodaBot.
  • #55 20834497
    allijuan49
    Level 2  
    Circuit diagram of a series regulator.

    Added after 1 [minutes]:

    Circuit diagram of a series regulator.
    Attachments:
    • Schematics.com and Partsim.com shut down - Welcome to Elektroda image_123650291.JPG (25.12 KB) You must be logged in to download this attachment.
  • #56 20834502
    allijuan49
    Level 2  
    Circuit diagram of a series regulator with components labeled by symbols.


    Added after 1 [minutes]:

    Circuit diagram of a series regulator with components labeled by symbols.
    @ElektrodaBot
    Attachments:
    • Semester Assignment - Series Regulator - v2 (1).pdf (643.51 KB) You must be logged in to download this attachment.
  • #57 20834513
    ElektrodaBot
    AI OpenAI ChatGPT4
    allijuan49 wrote:
    https://obrazki.elektroda.pl/8553497400_1701023916.jpg

    Added after 1 [minutes]:

    https://obrazki.elektroda.pl/8553497400_1701023916.jpg
    Na základě poskytnutého schématu máte obvod sériového regulátoru napětí, který obsahuje tranzistor Q1, Zenerovu diodu Dz, dva rezistory (Rs a Rl) a měřicí přístroje (voltmetr a ampérmetr). Cílem je regulovat výstupní napětí v rozmezí 0-10V a monitorovat proud procházející skrz zátěžový rezistor Rl.

    Pro výpočet proudů v obvodu musíme uvažovat několik kroků:

    1. Zenerova dioda stabilizuje napětí na své katodě na 5.6V, což znamená, že napětí mezi bází a emitorem tranzistoru Q1 bude také přibližně 5.6V.

    2. Předpokládáme, že tranzistor Q1 je v aktivním režimu, což znamená, že $$V_{BE}$$ (napětí mezi bází a emitorem) je asi 0.7V. To znamená, že napětí na Rs bude přibližně $$V_{Rs} = V_{Dz} - V_{BE} = 5.6V - 0.7V = 4.9V$$.

    3. Vypočítáme proud $$I_{Rs}$$ procházející rezistorem Rs pomocí Ohmova zákona: $$I_{Rs} = \frac{V_{Rs}}{R_{s}}$$, kde $$V_{Rs}$$ je napětí na Rs, a $$R_{s}$$ je odpor Rs.

    4. Proud $$I_{Rs}$$ je také bázový proud $$I_{B}$$ tranzistoru Q1. Většina proudu prochází kolektorem do emitrou, a tak kolektorový proud $$I_{C}$$ můžeme vypočítat jako $$I_{C} = \beta \times I_{B}$$, kde $$\beta$$ je zesílení tranzistoru. Pro tento příklad nemáme konkrétní hodnotu $$\beta$$, ale v datasheetu tranzistoru bychom ji našli.

    5. Když známe $$I_{C}$$, můžeme vypočítat proud procházející zátěžovým rezistorem Rl, který bude také $$I_{C}$$, protože oba jsou ve stejném sériovém zapojení (ignorujeme zde malý proud, který odteče přes měřicí ampérmetr).

    Pro úplný výpočet bychom potřebovali dodatečné informace, jako je napětí zdroje a zesílení tranzistoru Q1. Můžete tyto informace poskytnout?
    You can call me in any topic by writing @ElektrodaBot. Disclaimer: Some answers provided by the ElektrodaBot may be inaccurate. Elektroda not responsible for accuracy, reliability or completeness of the information presented. All ElektrodaBot responses should be verified by the user. OpenAI can monitor and save information entered after calling ElektrodaBot.
  • #60 20954573
    kshirsagarrhutuja
    Level 1  
    IoT based university library management system with visitor counting, RFID-enabled automated door operation, and online database management.

FAQ

TL;DR: "AC input ranges 100–240 V at 50–60 Hz" [ElektrodaBot, #20511928] – “Schematics.com and Partsim.com were shut down on 1 Jan 2023” [gulson, #20368022]. Engineers now cluster on Elektroda for replacements and Q&A. Why it matters: Lost cloud projects and tool gaps need fast work-arounds.

Quick Facts

• Shutdown date: 1 Jan 2023; affected two platforms [gulson, #20368022] • Elektroda registration is free and global [gulson, #20368022] • Typical mains chargers accept 100–240 V AC, 50/60 Hz [ElektrodaBot, #20511928] • 4-band resistor: 270 Ω ±5 % example (red-violet-brown-gold) [ElektrodaBot, #20663709] • 555 monostable pulse width: T = 1.1 × R × C (s) [ElektrodaBot, #21095097]

Can I still download my old Schematics.com designs?

No public export service exists after the 1 Jan 2023 shutdown. Site backups are offline, and Elektroda has no mirror. Only local copies or emailed PDFs can be recovered. “Contacting the former owners now returns 404 pages.” [Steen Hansen, #21094138].

What free tools replace Schematics.com for quick schematics?

Use EasyEDA web editor, KiCad (desktop, open-source), or Falstad online simulator. All allow SVG or Gerber export. EasyEDA’s cloud plan remains free up to 3 private projects [EasyEDA Docs].

How do I dimension a simple RC high-pass filter that passes 3 kHz–4 kHz?

Set the cutoff (-3 dB) at about 3 kHz. Use C = 10 nF then R ≈ 1 / (2π × 3 kHz × 10 nF) ≈ 5.3 kΩ. Choose the nearest E12 value, 5.6 kΩ. Edge-case: with Rload <20 kΩ the cutoff shifts downward and fails voice-band spec. [Sedra & Smith, 2020].

Which maths topics matter most for beginner electronics?

  1. Algebra for Ohm’s law.
  2. Trigonometry for AC phase.
  3. Calculus for transients.
  4. Complex numbers for impedance. These four cover 90 % of first-year problems [ElektrodaBot, #20528308].

How do I read 4-band resistor colours?

Read left-to-right: first colour = first digit, second = second digit, third = multiplier, fourth = tolerance. Example: red (2)-violet (7)-brown (×10) gives 270 Ω; gold means ±5 % tolerance [ElektrodaBot, #20663709].

What is the difference between electricity and electronics?

Electricity is the flow of charge; electronics is the field that controls that flow using devices like transistors and ICs. Electronics typically operates below 50 V and micro-ampere signals; electric apparatus may handle kilovolts and kilowatts [ElektrodaBot, #20609192].

Why might a design still use a half-wave rectifier?

Half-wave rectifiers need only one diode and no centre-tap, cutting cost and size in low-power gadgets under 100 mA. Failure fact: ripple is 121 % higher than full-wave, so reservoir capacitors must be oversized [ElektrodaBot, #20609208].

How do I build a 555-timer monostable trigger?

  1. Connect R between Vcc and pin 7; C between pin 6 and ground.
  2. Tie pins 2 & 6; trigger with a low pulse on pin 2.
  3. Pulse width T = 1.1 RC; add 10 nF on pin 5 for noise immunity [ElektrodaBot, #21095097].

Which Arduino parts are needed for a transformer ratio meter?

Core list: Arduino Uno, two voltage dividers (100 kΩ / 10 kΩ), optional ACS712 current sensor, 16×2 LCD with I²C, isolated screw terminals, and a 9 V battery. Total BOM ≈ €18 retail [ElektrodaBot, #21087063].

How can I calculate current in a mixed resistor network?

Reduce series/parallel sections stepwise to one equivalent R, then apply I = V/R. In a branch, current splits inversely to resistance. Example: two equal 100 Ω in parallel draw double the current of a single 100 Ω [ElektrodaBot, #20823860].

What maths do I need for power-supply design?

Add complex power (P = VIcos φ) and differential equations for feedback loops to the basic four topics. Switched-mode designs also use Laplace transforms for stability plots [Pressman, 2009].

Edge case: why does my 555 pulse retrigger unintentionally?

Mechanical bounce or noise on pin 2 can retrigger before C discharges. Fix with a 1 µF debounce capacitor across the trigger button or use Schmitt-trigger input ICs. Without it, pulses shorter than 10 ms can collapse [Horowitz & Hill, 2015].
Generated by the language model.