Calculating Pull-Out Torque in Synchronous Machines: Electrical vs Mechanical Factors

Hi, I'm taking a power course this summer, and have some questions regarding what is referred to as pull-out torque.

My understanding is that pull-out torque is based on the induced voltage and impedance of a machine and its fields rather than being a mechanical function.

if the mechanical torque level over steps the electrical pull-out level, then the machine's fields fall out of sync, massive amounts of current flow in the opposite direction and generally bad stuff happens.

My question is basically do you have to account for the other mechanical factors when calculating the pull-out torque level or is it more based on the fields and electrical side.

Thanks

Pull-out torque is the maximum possible torque of the motor. Depending on what you mean by "mechanical factors" the equation for pull-out torque of an induction motor appears to only have electrical parameters.

[tex]tau_{max} = frac{3V_{TH}^{2}}{2omega_{sync}left [ R_{TH}+sqrt{R_{TH}^{2}+left ( X_{TH}+X_{2} right )^{2}} right ]}[/tex]