Convert 9 V battery into two separate 1.5 mv currents

I am looking to design a small box that houses a single 9-V battery (as power supply), and has two anodes (separate wires) and two cathodes (also separate wires) as outputs.

I need for the current to get 1.5 Mv coming out of each anode (to flow across a surface to get to the respective cathode) , and it is important that not go above this value.

Can anybody help me design the appropriate circuit to try out on my breadboard. Not sure what I would need or how to do it.

Thanks,

Jeff

Is the correct?

Specs:
Two galvanically isolated (totally separate) outputs of 1.5 mV (that's 0.0015 volts)

Jeff
you have to split the circuit, you could use a Zener diode for both "but", the questions is what is the voltage rating for the load...

David