Hello!
Please help me solving my school task. So I have sine-wave source of 240V, two ideal transformers with ratios 1:10 and 10:1 and some load. Between two ideal transformers, there is wire-resistance 2 x 0.1 Ohm and schematics state that current flowing trough Load is 50A.I need to calculate = Voltage on Load (Vload), power dissipated on Load (Pload), power dissipated on those wires between transformers and overall system efficiency = Pload/Psupply
From my own understanding I estimated that there will be 2400 Volts and 5 amps between those two transformers, but because of wire resistance voltage drop will be 5*0.2 = 1V so 2400-1 = 2399 and there will be 2399/10 = 239.9 Volts on Load side. And load resistance is 239.9/50 = 4.798 Ohms. So dissipated power on Load is 50^2 * 4.798 = 11995 Watts and power dissipated on wires between transformers = 5^2*0.2 = 500Watts. Am I correct?
Please help me solving my school task. So I have sine-wave source of 240V, two ideal transformers with ratios 1:10 and 10:1 and some load. Between two ideal transformers, there is wire-resistance 2 x 0.1 Ohm and schematics state that current flowing trough Load is 50A.I need to calculate = Voltage on Load (Vload), power dissipated on Load (Pload), power dissipated on those wires between transformers and overall system efficiency = Pload/Psupply
From my own understanding I estimated that there will be 2400 Volts and 5 amps between those two transformers, but because of wire resistance voltage drop will be 5*0.2 = 1V so 2400-1 = 2399 and there will be 2399/10 = 239.9 Volts on Load side. And load resistance is 239.9/50 = 4.798 Ohms. So dissipated power on Load is 50^2 * 4.798 = 11995 Watts and power dissipated on wires between transformers = 5^2*0.2 = 500Watts. Am I correct?
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