Any Availability of direct clipper IC with input voltage ranges from -100v to 100v.

Hello,


I am working on an application, which requires to convert a biphasic pulse wave with amplitude ranges from - or +100v to - or +3.3v. I need to use an Clipper circuit in IC form. Can anyone please suggest me, are there any commercialized clipper IC's available to purchase. Any help is very much appreciated. Thanks in advance.


Thanks,
Jagadeesh. 

I am not sure why you couldn’t use resistors and diodes to clip the waveform, but if you can’t you might want to look at TI’s range of high common mode input voltage differential amplifiers (http://www.ti.com/amplifier-circuit/difference/products.html#p1169max=100;500 ) that could be used to clip, used like a comparator.Good luck.

Hello  Aubrey,
Thank you very much for your response. I think it is better to avoid too many components in my design, I mean to say in my application, I need to use 64 clipper circuits for 64 channels. So if I use resistors and diodes, I think my circuit may occupy more space on board. So I am looking for a single IC, which serves the purpose of converting 0-100v pulse into 0-3.3v pulse.I have gone through the TI's differential amplifier data sheet. If I am not wrong, it has large input common mode range but not the differential mode range. I mean my input range is from 0-100 V, but it has only differential input voltage of -13.5 V to +13.5 V. So I think it does not serve the purpose. Can you please validate my thought?.If I am correct, can you please suggest me an other candidate, who serves better. If not can you please explain, how can I use this IC. The IC, that I am looking at is attached here. I look forward to hearing from you soon.Thanks,Jagadeesh.

Hi Jagadeesh-A little more information please- You want to get rid of amplitude information and just keep pulse width information.  Is that correct?If that's what you need, then I think Aubrey's suggestion of a comparator will be a good solution. You won't have to use a high voltage comparator if you use a voltage divider on the incoming signal.-Rick

@ Rick,
Hello Rick, Your assumption is correct. I just want to get rid of the voltage but the same pulse width and at the same time I don't want to use voltage divider circuit, which makes my design it complex in terms of area consumption, since I need to use 64 Clippers for 64 channels in my application. Hence, I am looking for a single IC, which serves the purpose.
Thanks,Jagadeesh.

As near as I can tell, you can apply +/- 275V at any input. The 13.5v is the range for the amplifier to work in its linear range. I was thinking you could use it like a comparator and tie the -ve to ground. A high positive voltage on the +ve inputwould cause the output to saturate  at maximum output (close to the positive supply) and vice versa.Some amplifiers suffer from phase inversion when you overdrive the inputs,  that is the output flips over to the other polarity. I don’t know if the INA149 does that.  I would think this would be worth the exercise of trying I don’t believe you will find  anything else.Added later:This may not work- you should read the section  “COMMON MODE RANGE’” on page 14 of the INA149 data sheet  regarding the internal voltage limits. http://www.ti.com/lit/ds/symlink/ina149-ep.pdf