Hello. So I wrote this program: The problem is that if I do not enter a number, but e.g. the letter L, some strange characters appear, and I would like it to show e.g. This is not a number. There is one more problem that if I give it 0 to a and 0 to b, it will show me that there are infinitely...

You declared the condition incorrectly, which means that the value of x always counts regardless of the event. You can do this: Code: text Expand Select all Copy to clipboardint main() { float int a; float int b; float int x; cout

My friend akartians , using goto makes no sense here. Why not use a while loop? This can be solved simply by adding else: Code: text Expand Select all Copy to clipboard if (a==0 && b==0) cout

Where did you use the while loop? The first source code works, but the second one shows Error and some characters :D Added after 2 [minutes]: OK, I solved the problem, thank you all for your help.

I haven`t used it, but my friend wants an example, so here you go: Code: text Expand Select all Copy to clipboard while(true) { cout a; cout b; if (a==0 && b==0) cout

Handling Non-Numeric Input and Division by Zero in C++ Linear Equation Solver

mgpentium 20628 4

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#1 7031609 18 Sep 2009 15:22

mgpentium mgpentium

Level 16
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Post #1
7031609 18 Sep 2009 15:22

Hello.
So I wrote this program:

Code: text Expand Select all Copy to clipboard
int main() { float a; float b; float x; cout << " licze rownanie liniowe, pierwszego stopnia, z jedna niewiadoma.\n"; cout << " ax+b=0\n"; cout << "Podaj a: "; cin >> a; cout << "Podaj b: "; cin >> b; if (a==0 && b==0) cout << "Nieskonczenie wiele rozwiazan\n"; else if (a==0 && b!=0) cout << "Brak rozwiazan\n"; x=-b/a; cout << "x = "<<endl; }

The problem is that if I do not enter a number, but e.g. the letter L, some strange characters appear, and I would like it to show e.g. This is not a number.
There is one more problem that if I give it 0 to a and 0 to b, it will show me that there are infinitely many solutions and also some other strange characters, and I would like these characters to be absent.

Please place the code in code tags - krzychoocpp
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#2 7031668 18 Sep 2009 15:40

akartian akartian

Level 11

Post #2

7031668 18 Sep 2009 15:40

You declared the condition incorrectly, which means that the value of x always counts regardless of the event. You can do this:

int main()
{
float int a;
float int b;
float int x;
cout << " licze rownanie liniowe, pierwszego stopnia, z jedna niewiadoma.\n";
cout << " ax+b=0\n";
stat:
cout << "Podaj a: ";
cin >> a;
cout << "Podaj b: ";
cin >> b;

if (a==0 && b==0) 
{
cout << "Nieskonczenie wiele rozwiazan\n";
goto stat;
}
else if (a==0 && b!=0) 
{
cout << "Brak rozwiazan\n";
goto stat;
}
x=-b/a;
cout << "x = "<<endl;

The goto instruction is usually not used because the program is not very readable, but it can be done quickly.

Please place the code in code tags - krzychoocpp

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#3 7031690 18 Sep 2009 15:46

krzychoocpp krzychoocpp

VIP Meritorious for electroda.pl
» | Helpful post? (0)

Post #3
7031690 18 Sep 2009 15:46

My friend akartians , using goto makes no sense here. Why not use a while loop?

This can be solved simply by adding else:

Code: text Expand Select all Copy to clipboard
if (a==0 && b==0) cout << "Nieskonczenie wiele rozwiazan\n"; else if (a==0 && b!=0) cout << "Brak rozwiazan\n"; else { x=-b/a; cout << "x = "<<endl; }

Checking whether the variable loading was successful:

Code: text Expand Select all Copy to clipboard
cout << "Podaj a: "; cin >> a; if(cin.fail()) cout << "Blad" << endl;

Regards Krzysztof.
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#4 7031771 18 Sep 2009 16:12

mgpentium mgpentium

Level 16
» | Topic author Helpful post? (0)

Post #4
7031771 18 Sep 2009 16:12

krzychoocpp wrote:
My friend akartians , using goto makes no sense here. Why not use a while loop?

This can be solved simply by adding else:

Code: text Expand Select all Copy to clipboard
if (a==0 && b==0) cout << "Nieskonczenie wiele rozwiazan\n"; else if (a==0 && b!=0) cout << "Brak rozwiazan\n"; else { x=-b/a; cout << "x = "<<endl; }

Checking whether the variable loading was successful:

Code: text Expand Select all Copy to clipboard
cout << "Podaj a: "; cin >> a; if(cin.fail()) cout << "Blad" << endl;

Regards Krzysztof.

Where did you use the while loop?
The first source code works, but the second one shows Error and some characters :D

Added after 2 [minutes]:

OK, I solved the problem, thank you all for your help.

#5 7031876 18 Sep 2009 16:42

krzychoocpp krzychoocpp

VIP Meritorious for electroda.pl

Post #5

7031876 18 Sep 2009 16:42

I haven`t used it, but my friend wants an example, so here you go:


while(true)
{
  cout << "Podaj a: "; 
  cin >> a; 
  cout << "Podaj b: "; 
  cin >> b; 

  if (a==0 && b==0) cout << "Nieskonczenie wiele rozwiazan\n"; 
  else if (a==0 && b!=0) cout << "Brak rozwiazan\n";
  else 
  { 
        x=-b/a; 
        cout << "x = "<<endl; 
        break;
  }
}

The program will ask for the parameters of the equations until there is one solution.

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