[C++] Determine Gender Based on First Name: Analyzing Last Character in a Char String

Hello,
I have been dealing with the basics of programming for a long time (pascal, java, c / c ++).

One exercise bothers me.

I want to write a program where the user gives the first name.
The program checks the string of characters and determines whether you are a man or a woman.

In terms of theory, it would rather look like this:
We assume a string string name [15]
we get the name with cin stream.
When the last letter of the name is "a" in the conditional instruction, gender-female is displayed on the screen, otherwise gender-male, exception: male-male name.

And here's my question, how do I check the last character of the char string?

I know, these are the basics, as of today I am helpless ...

I am asking for tips, help.

You're a bit confused.
is a 15-element array of strings (i.e. an array of 15 words). And the array char name [15] is one string (that is, one word).

How do I find the last letter? Very simply, each word loaded into the array ends with the character '\ 0', so we need the penultimate element.
[code:1:851f968178]
#include

using namespace std;


int main()
{
char imie[15];
cout imie;

char znak_konca= '\0';
//sprawdzenie czy kuba?
if(imie[0]=='k' && imie[1]=='u' && imie[2]=='b' && imie[3]=='a')
{
cout

Ok, thanks a lot for your help.
Yes you are right it has to be char - a string, not a string.

I'm just still considering a solution through strlen

The name Kuba is a kind of diminutive of the name Jakub, so the algorithm does not have to be an exception in this case. But that's a bit off topic.
Regards

Well no - it doesn't have to be a char array - as long as it is to be done in C ++! Everything is easier in C ++:
[code:1:1ebfb3b875]string imie;
cout > imie;
if( imie == "Kuba" ){
cout

Thanks, I modified your program and I have something like this:


[code:1:1a98bceb00]
...
if( (imie[imie.size()] == 'a') && (imie != "Kuba") )
cout