Hello
Here is perhaps the easiest solution :)
As you can see, resistors R1 and R2 are connected in parallel and resistors R3 and R4 are connected in series.
First you need to calculate the equivalent resistances. For parallel connection of two resistors it is assumed
formula (R1 * R2): (R1 + R2)
Calculation 1
All resistances are 3 ohms
so: (3 * 3): (3 + 3) = 9: 6 = 9/6 = 3/2 - the result is a fraction
The equivalent resistance of R1 and R2 is 3/2 Ohm
R1.2 = 3/2 Ohm
Calculation 2
Resistors R3 and R4 are connected in series so their resistances add up
R3 + R4 = 3 + 3 = 6 Ohm
The equivalent resistance of the resistors R3 and R4 is 6Ohm
R3.4 = 6 ohms
After these treatments, we get a schcamt from the top of the picture.
Now we should sum up the calculated equivalent resistances R1.2 and R3.4. These resistances are connected
in parallel.
So the equivalent resistance R1,2,3,4 is equal to = (R1,2 * R3,4): (R1,2 + R3,4) = (3/2 * 6): (3/2 + 6) =
= 18/2: (3/2 + 18/2) = 9: 21/2 = 9 * 2/21 = 18/21 Ohm
R 1, 2, 3, 4 = 18/21 ohm
The current according to Ohm's law is equal to the supply voltage through the resistance
I = U: R = 3V: 18/21 Ohm = 3V * 21/18 = 63/18 = 3.5 A
And it's probably over.
In case of any errors, please improve (I am still learning myself -> IB Technical School of Electronics in Stalowa Wola