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How to Calculate Circuit Current with U=3V and Four Equal Resistors R1=R2=R3=R4=R?

rogra 35259 7
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  • #1 1057632
    rogra
    Level 13  
    here is the content :O CALCULATE THE CURRENT CIRCUIT. DATA: U = 3V, R1 = R2 = R3 = R4 = R, R3OM HERE'S THE DRAWING. HELP IN SOLUTION, THANK YOU IN advance
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    #2 1057701
    Mariusz Ch.
    VIP Meritorious for electroda.pl
    Hello.

    You calculate the equivalent resistance. R1iR2 connected in parallel and the resultant 1 / 2R. R3iR4 in series - resultant 2R.
    Then the parallel connection of R / 2i2Rto gives Rz = 2R / 5.
    I = U / Rz.

    you calculate the rest.

    Kisses
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  • #3 1057713
    rogra
    Level 13  
    I would like to ask for a detailed answer for the skin, thank you in advance
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    #4 1057797
    Mariusz Ch.
    VIP Meritorious for electroda.pl
    Hello.


    Ojjjjjjjjjjjjjjjjjj.

    you calculate the equivalent resistance of the entire circuit.

    1 / Rz = 1 / R1 + 1 / R2 + 1 / (R3 + R4) the latter term in the denominator has a series connection of R3 and R4.

    Equivalent resistance of series connection of n resistors

    Rzs = R1 + R2 + R3 + R4 + .... Rn

    Equivalent resistance of a parallel connection of n resistors

    1 / Rz = 1 / R1 + 1 / R2 + 1 / R3 + 1 / R4 + ....... 1 / Rn

    Now the school rule: to add fractions, they must be brought to a common denominator.

    the fact that R1 = R2 = R3 = R4 simplifies things

    1 / Rz = 1 / R + 1 / R + 1 / 2R

    1 / Rz = 2 / 2R + 2 / 2R + 1 / 2R

    1 / Rz = 5 / 2R

    Rz = 2R / 5

    Rz = 2/5 times R.

    I = U / R for R you substitute computed Rz

    I = U / Rz
    I = U / 2R / 5
    I = 5U / 2R

    I = 5 times 3V divided by 2 times 3 Ohm
    I = 2.5A

    I think everything is clear now.

    I have only one request : Pick up the books and study a bit .

    This is not an insult, but good advice. It pays off in the future.


    Kisses : turn-l:
  • #5 1057879
    rogra
    Level 13  
    I understand something of this, but not quite, thanks for your help, maybe something will come out of it, I will tell you honestly I am already calculating this task from Saturday, I am not missing something, I probably counted 10 times and I do not know, so I would ask for the whole solution for which I thank in advance
  • Helpful post
    #6 1058316
    magik128
    Level 22  
    Hello

    Here is perhaps the easiest solution :)

    As you can see, resistors R1 and R2 are connected in parallel and resistors R3 and R4 are connected in series.
    First you need to calculate the equivalent resistances. For parallel connection of two resistors it is assumed
    formula (R1 * R2): (R1 + R2)

    Calculation 1
    All resistances are 3 ohms

    so: (3 * 3): (3 + 3) = 9: 6 = 9/6 = 3/2 - the result is a fraction
    The equivalent resistance of R1 and R2 is 3/2 Ohm
    R1.2 = 3/2 Ohm

    Calculation 2
    Resistors R3 and R4 are connected in series so their resistances add up

    R3 + R4 = 3 + 3 = 6 Ohm
    The equivalent resistance of the resistors R3 and R4 is 6Ohm
    R3.4 = 6 ohms

    After these treatments, we get a schcamt from the top of the picture.

    Now we should sum up the calculated equivalent resistances R1.2 and R3.4. These resistances are connected
    in parallel.

    So the equivalent resistance R1,2,3,4 is equal to = (R1,2 * R3,4): (R1,2 + R3,4) = (3/2 * 6): (3/2 + 6) =
    = 18/2: (3/2 + 18/2) = 9: 21/2 = 9 * 2/21 = 18/21 Ohm

    R 1, 2, 3, 4 = 18/21 ohm

    The current according to Ohm's law is equal to the supply voltage through the resistance
    I = U: R = 3V: 18/21 Ohm = 3V * 21/18 = 63/18 = 3.5 A

    And it's probably over.
    In case of any errors, please improve (I am still learning myself -> IB Technical School of Electronics in Stalowa Wola :)
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  • #7 1058877
    qmpel
    Level 16  
    Hey !!

    ... and this job (mail) generally I can see that guys magician128 and Mariusz Ch. They have already given you a clear solution and if you do not understand it, it is difficult with you, I do not know if it is because of laziness you cannot solve tasks like this, because it is probably not the first one on the forum, or for some other reasons ... I am sending http link : //www.elektroda.pl/rtvforum/viewtopic.php? p = 1042365 & highlight = # 1042365 with a similar task (see my post), in which it is probably explained how to solve this type of task, because there is no point in rewriting it and repeating the above-mentioned colleagues. Compare and Solve for yourself is more fun than ready-made.

    Greetings !!
  • #8 1058911
    rogra
    Level 13  
    PLEASE CLOSE THIS FAST AS EVERYTHING IS KNOWN

Topic summary

The discussion revolves around calculating the current flowing in a circuit with given parameters: voltage (U = 3V) and resistors (R1 = R2 = R3 = R4 = R). Participants explain how to determine the equivalent resistance of the circuit, which involves both parallel and series connections of resistors. The equivalent resistance is calculated as Rz = 2R / 5, leading to the current calculation I = 5U / 2R, resulting in a current of 2.5A. Several users request further clarification and detailed solutions, while others provide links to similar problems for additional guidance.
Summary generated by the language model.
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