I took a closer look at your diagram and it makes no sense if V1, V2 & V3 are voltmeters and A is an ammeter -- unless V1 = V2 = V3 = I = 0. Because there is no power source.
But, if you are looking for a meter to give you V3/I, then it sounds like you need an Ohmmeter, like some of the others have said.
In other words, V3/I = the resistance of whatever V3 is across. Now, if the component that V3 is across is not a linear positive resistance, or if it is, and at V3 it's being stressed in a way that would change it's resistance, then you will need two meters. One a voltmeter and the other an ammeter, and then some sort of dividing function -- since an ohmmeter will apply it's own voltage which will likely not be whatever V3 is.
So, maybe what you're looking for is the dividing function. There are several ways to do that, so let us know if that is what you want, and I/we will elaborate.
