Resistances of Two Parallel Resistors With 10V Supply, 3A in One, 50W Total Power?

60 9

#1 21662360 27 May 2012 20:02

Richard Bosanquet Richard Bosanquet

Anonymous

Post #1
21662360 27 May 2012 20:02

The total power consumed by two resistors, connected in parrellel, is 50watts if the applied voltage is 10volts dc and the current thought one resistor is 3 amperes what are the resistances of the two resistors ?
How do you calculate it ??
ADVERTISEMENT
#2 21662361 27 May 2012 21:07

Yun Siong Leong Yun Siong Leong

Anonymous

Post #2
21662361 27 May 2012 21:07

P=(v^2)/R then use kirchoff current divider formular to get the current of each resistor then you can obtain the value easily
ADVERTISEMENT
#3 21662362 27 May 2012 21:23

BHARADWAJ ACHARYA BHARADWAJ ACHARYA

Anonymous

Post #3
21662362 27 May 2012 21:23

As the resistances are in parallel the equivalent resistance is R= R1*R2/(R1+R2)
and also the current in one of the resistance is 3 amps so , say if that resistance to be R1 then R1=V/I=10/3.
So substitute R1 in R and also the power dissipated is 50 watt ,
So P= V*R = 10 * (R1*R2/(R1+R2)) = 10 * ((10/3) *R2/((10/3)*R2)) = 50W , thus you get both R1 and R2.

Hope this helped.
#4 21662363 28 May 2012 00:12

Otto Sponring Otto Sponring

Anonymous

Post #4
21662363 28 May 2012 00:12

On eresistor is 3.333Ohm and the other is 5Ohm
To get 50W at 10V you need to have 50/10=5A. One resistor is 3A then the other must have 2A.
R=U/I that gets you the 2 resistors.
#5 21662364 28 May 2012 00:50

Frank Bushnell Frank Bushnell

Anonymous

Post #5
21662364 28 May 2012 00:50

With greatest respect to everyone, I think that Richard (who is an apprentice electrician) will derive far greater benefit if he does his own homework, rather than getting other people to do it for him.

Richard, do your own coursework. You have been taught the principles in class, and you have a textbook to revise them if you need to. If you don't do the work yourself now, you fail your exams.
ADVERTISEMENT
#6 21662365 03 Jun 2012 09:32

Yun Siong Leong Yun Siong Leong

Anonymous

Post #6
21662365 03 Jun 2012 09:32

Are you sure that you give the equation P=V*R? I don't think so. If you want to obtain the resistance from power equation, the proper equation is P = (V^2) / R or you can use another equation, R = (V^2) / P.
#7 21662366 04 Jun 2012 02:55

BHARADWAJ ACHARYA BHARADWAJ ACHARYA

Anonymous

Post #7
21662366 04 Jun 2012 02:55

Yeah man you are right!! I was wrong with the equation. P= V*I and P=V^2/R), yet the concept remains the same instead of P=V*I we have to substitute inR = (V^2) / P.
#8 21662367 10 Jun 2012 22:26

Richard Bosanquet Richard Bosanquet

Anonymous

Post #8
21662367 10 Jun 2012 22:26

Thanks all,
Hi frank
I'm not an apprentice yet, I am working in a completely different industry I am doing the course via correspondence. if I send my teacher a question i have to wait about 3-4 days for a reply or I can come on here ask a question and I can read all the views / replys that people have left for me. I find this a better way to understand the topic then wait for days for my teacher to get back to me.
ADVERTISEMENT
#9 21662368 11 Jun 2012 00:04

Frank Bushnell Frank Bushnell

Anonymous

Post #9
21662368 11 Jun 2012 00:04

Hi Richard, thanks for your message.
Please forgive me if I have misunderstood you. It's just that quite regularly on this forum, it does appear that some electrical engineering students will just cut and paste in their coursework questions !
All the best, Frank.

Here are a few useful instructional sites:

http://www.satcure-focus.com/hobby/index.htm - Useful ideas tutorials circuits links etc

http://www.allaboutcircuits.com - online textbooks covering electricity and electronics

http://electronics-for-beginners.com/links.php

http://openbookproject.net/electricCircuits/

http://www.ecelab.com/index.html - Electronics & Communications Engineering - from basic concepts

http://www.eleinmec.com/index.asp - Electronics in Meccano - Useful basics of electricity
#10 21662369 11 Jun 2012 00:27

Richard Bosanquet Richard Bosanquet

Anonymous

Post #10
21662369 11 Jun 2012 00:27

Thanks frank
I do want to learn it Im shit scared of Zapping my self to death lol
Thanks
I will save the sites
Thanks again all
Create an account, log in here. You will receive points by participating in discussions.
Join this discussion.

Install Elektroda application

Didn't find an answer? Ask Artificial Intelligence

*I agree to send the question to OpenAI, Anthropic PBC, Perplexity AI, Inc., Kagi Inc., Google LLC - owners of language models in order to prepare the best response. The companies may monitor and log information entered into the form.

*I agree to publicly display my question and answer. The question and answer will be publicly available to everyone. The process may take a few minutes. Upon completion, you will be redirected to the page with the answer.

Wait...(2min)

Topic summary

The discussion addresses calculating the resistances of two parallel resistors supplied with 10 V DC, where the total power dissipation is 50 W and one resistor carries 3 A current. The correct approach involves using the power formula P = V² / R to find resistance values. Given one resistor current (I₁ = 3 A), its resistance is R₁ = V / I₁ = 10 V / 3 A ≈ 3.33 Ω. The total current is I_total = P / V = 50 W / 10 V = 5 A, so the second resistor current is I₂ = 2 A, yielding R₂ = V / I₂ = 10 V / 2 A = 5 Ω. The equivalent resistance R_eq of the parallel combination is R_eq = (R₁ * R₂) / (R₁ + R₂). The discussion also clarifies common misconceptions about power formulas, emphasizing the correct use of P = V² / R rather than P = V * R. Additional resources for learning electronics fundamentals were shared to support independent study.
Summary generated by the language model.

Resistances of Two Parallel Resistors With 10V Supply, 3A in One, 50W Total Power?

Didn't find an answer? Ask Artificial Intelligence

Topic summary