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Understanding 690V Voltage Origin in Star and Delta Motor Connections

lorakw 23179 4
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Treść została przetłumaczona polish » english Zobacz oryginalną wersję tematu
  • #1 10766915
    lorakw
    Level 10  
    Hello!
    I have a question about the delta and star connection. I know that if the motor is connected in a star, the voltage will be 230 V, and if the motor is connected in a triangle, it will be 400 V. After reading a few topics on the forum, I also learned about a voltage of 690V when connected in a star. Where does it come from? 230*3?
    greetings and Merry Christmas!

    It is taken from the normal 3x400V mains. You don't have to take anything - this is a parameter that determines the work of the windings when connected in star and delta with a switch.
    If there is an inscription on the nameplate
    230/400 or (220/380) This means that it can only work star-coupled.
    380V/660V (400V/690V - approx. -> 400V x √3 = 690V ) connected to the mains can work both star- and delta-coupled. Then you can use the λ/Δ switch to reduce the starting current of the motor (unless the motors were rewound according to someone's "wish").
    In the first case (230/400) the motor can work with a voltage of 3x230 connected in delta, but powered by an inverter, i.e. powered with a voltage of 3x230V
    [Acres]
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  • #2 10766937
    MARCIN.SLASK
    Home appliances specialist
    I think it is similar to 400V voltage (400V phase-to-neutral, 230V phase-to-neutral), here (690V phase-to-phase, 400V phase-to-neutral).
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  • #3 10767045
    12pawel
    Level 34  
    230V x √3 = 400V
    400V x √3 = 690V
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  • #4 10767243
    lorakw
    Level 10  
    I got a little carried away with everything. But I already know that the first value is the effective value and the second is the maximum value. Thanks for the replies. Regards
  • #5 11092228
    sq9jjh
    Electrician specialist
    lorakw wrote:
    I got a little carried away with everything. But I already know that the first value is the effective value and the second is the maximum value. Thanks for the replies. Regards

    However, my colleague managed to do it, please carefully read what Akrzy74 wrote in red.
    For it to be 690V, there would have to be a specially built network (transformer) in which the phase-to-phase voltage is 690V, and the voltage of 1 phase between the neutral point would then be 400V.
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