WędkarzStoLica wrote:
Rzuuf wrote:
If the voltage of a 12-volt battery drops below 10.8V, you can basically say goodbye to it.
Don't write such nonsense because someone else will believe it and throw away a working battery.
This is not nonsense but theory
WędkarzStoLica wrote: How do you explain a twice discharged battery to zero, 3 years have passed and it is still fine.
This is practice.
Rzuuf wrote: And the explanation of this miracle is expected from you, because you are the one who observed it!
I will try according to my knowledge and practice somewhere I saw a graph of the life of a given battery when discharging 20% the life was 80%. And at 80% discharge the life was 20%. At stronger discharges of 100% of the battery capacity( voltage 11.8V without load) the amount of additional energy gained is not great and the battery consumption is not comparatively greater. With even greater discharges, the non-proportional consumption of the battery is even greater after one such cycle is lost several normal cycles.
''1. Charged battery
A fully charged battery on the negative electrode side (–) contains lead (Pb) in the plates, and on the
positive electrode side (+)contains lead dioxide (PbO2) in the plates. The electrolyte is a solution of
sulfuric acid (H2SO4) and water (H2O) in a ratio of 37:63.
2. Discharging the battery
When the receiver is connected, electrons in the external circuit flow from the anode (Pb) to the cathode
(PbO2). These electrons come from the reaction of lead with SO4 ions
2– from the solution. Lead releases two electrons
(they are the current carriers in the external circuit) and forms the compound PbSO4 Whereas
the electrons flowing from the external circuit to the cathode of PbO2 cause two reactions: one, is
the detachment of oxygen ions from PbO2 and the formation, together with electrons and H+ ions from the solution – molecules of
water, and the other, is the reaction of lead with SO4 ions giving again PbSO4 As a result, on both electrodes
the same compound PbSO4 2 is formed
During the operation of the battery in the solution, SO4 ions are lost and more and more water molecules are formed.
The solution is diluted, and the same compound PbSO4 is formed on both electrodes.
3. Completely discharged battery
The lead sulfate (PbSO4) that is lost from the solution crystallizes and deposits on both electrodes increasingly
thick layer, and there is an increasing percentage of water in the electrolyte. When the battery is
completely discharged several times, then the lead sulfate forms a layer thick enough to act as an insulator.
The battery loses its properties, reduces its capacity, as a result of which it is destroyed''
When discharging/charging the plates work mechanically( lead sulfate has a larger volume than lead and lead dioxide) after each cycle not a large part of the mass of the plates falls to the bottom. Thick lead crystals dissolve only at a voltage much higher than the buffer voltage (2.4V for the purposes is sufficient) and a small charging current in order not to damage the plates. The battery can be discharged to zero and desulfurized any number of times the only delimitation is the mechanical wear resistance of the plates to which only remelting in a smelter will help.