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Choosing the Right Resistor for 12V 0.3W LED Indicators: Replacing 12V 21W Motorcycle Bulbs

Mromat 35436 7
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Treść została przetłumaczona polish » english Zobacz oryginalną wersję tematu
  • #1 15651451
    Mromat
    Level 9  
    Hello,
    Can someone help in choosing a resistor? I want to replace the two indicators on the back of the moto. Earlier bulbs were 12V / 21W. The new LED indicators are 12V / 0.3W - What resistor should be used in parallel to make it work and keep the old flashing frequency? They flash too fast (I say right away that the change of the circuit breaker / relay is gone for sure)
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  • #2 15651495
    lukasixthm
    Level 23  
    There are special interrupters for LED turn signals, and if you do not need to replace it, you must select the resistor experimentally. Start with 680ohm 2W and run down if it was still too fast.
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  • #3 15651511
    Mromat
    Level 9  
    Down? So reduce Ohms and Watts? Can you tell me what this is coming from? What patterns? I found something that the old bulbs gave a current of 1.75, so from 21W they gave about 7 Ohms, so a similar resistor (8-10 Ohm) should be used? I found that people wrote 25 W 8 Ohms but I would like to know at least in theory what it comes from.
  • #4 15652252
    Anonymous
    Anonymous  
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    #5 15652303
    WRadek
    Level 23  
    For Elektronik987:
    Unfortunately, you do not know how the flasher unit on motorcycles works. And your argument is generally correct, but not in this case.

    To lukasixthm:
    Downward - that is, towards less and less resistance, i.e. less and less Ohms, but more and more power dissipated on the resistor. So talk less about more watts.

    As long as you do not replace the circuit breaker with one adapted to the LED indicators, you will not have savings on electricity. But if you don't care about it, you have to hit this resistor.
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    #6 15652311
    lukasixthm
    Level 23  
    Buddy Elektronik987, the resistor in question is as if instead of a light bulb. So in parallel with the "LED bulb". This is because inserting the LEDs changes the blinking frequency. The breaker is designed in such a way that it breaks faster after, for example, a light bulb burns out. I don't know if it's a deliberate intention, I didn't delve into it.

    When connecting the LED, we have to cheat the circuit breaker with this resistor with a resistance similar to the resistance of the hot fiber (10ohm). Then the supply voltage (14V) is deposited on it, so it must be of correspondingly higher power (20W).

    Buddy Mromat. When I said down, I meant lowering the resistance and therefore increasing the watts. Ohma law. Little off top - I recommend you the ElektroDroid smartphone application. It will help you with many simple problems.
  • #7 15654058
    Mromat
    Level 9  
    Thank you all. I bought what the seller suggested in the electronics store - 50W6R8J (apparently 6.8 Ohm I was surprised myself that it has just such a value, but it supposedly comes from 12V / 1.75A) and it works as it should - the lighting frequency is appropriate. The resistor has a heat sink, and apparently more power in my case means less resistor heat and a higher price. Fellow motorcyclists on foreign forums put 25W8R resistors on 1-3W LEDs and they also worked.
    Question - do such combinations affect the service life of the circuit breaker?
  • #8 15654078
    bambus94
    Level 34  
    It affects, but in my opinion positively, because the cold filament of the bulb is about 1R, which causes a short increased power consumption. And the resistor has a constant 6R8 and the diode is a fraction of this current.

Topic summary

The discussion revolves around selecting an appropriate resistor to replace 12V 21W motorcycle bulbs with 12V 0.3W LED indicators while maintaining the original flashing frequency. Users suggest starting with a 680 ohm, 2W resistor and adjusting downwards if the flashing is too fast. The importance of understanding the motorcycle's flasher unit is emphasized, as it is designed to detect bulb failures by monitoring current draw. A resistor is needed in parallel with the LED to simulate the load of the original bulb, with recommendations for a 6.8 ohm, 50W resistor based on the original bulb's current draw. The impact of resistor choice on the circuit breaker's lifespan is also discussed, with some users noting that a lower resistance can lead to more stable operation.
Summary generated by the language model.
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