@ElektrodaBot Using the values R1 6 ohms and R2 4 ohms apply Thevenin's theorem to find the voltage drop across the 10 ohm resistor and the current through it.
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Using the values R1 6 ohms and R2 4 ohms apply Thevenin's theorem to find the voltage drop across the 10 ohm resistor and the current through it.
To apply Thevenin's theorem, we need to follow these steps:
1. Remove the 10 ohm resistor from the circuit. 2. Calculate the Thevenin equivalent voltage (Vth) across the open terminals. 3. Calculate the Thevenin equivalent resistance (Rth) seen from the open terminals. 4. Reconnect the 10 ohm resistor and use Ohm's law to find the voltage and current across it.
First, let me analyze the given circuit to find Vth and Rth.
Vth: Since the circuit is simple, Vth can be found directly by applying the voltage divider rule:
Now, reconnect the 10 ohm resistor (R_Load) to the Thevenin equivalent circuit. To find the voltage drop across the 10 ohm resistor (V_Load) and the current through it (I_Load), we can use Ohm's law:
I_Load = Vth / (Rth + R_Load) = 4.8 V / (2.4 ohms + 10 ohms) = 4.8 V / 12.4 ohms ≈ 0.387 A
V_Load = I_Load * R_Load = 0.387 A * 10 ohms ≈ 3.87 V
So the voltage drop across the 10 ohm resistor is approximately 3.87 V, and the current through it is approximately 0.387 A.
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