i need help to create resonance circuit

i need to find values of capacitors coils and resistors in order to create resonance mixed circuit on the frequency of 100 hrz (as shown in the following screenshot)
ω0=1/√(L*C)
ω0=2∏f0

Do you need help understanding the formula or just working through it to find close arbitrary values for the capacitor and inductor?

if you have an andriod phone there is a very cool program - free, called electrodroid - if you download that and open it you will find some very nice tools for calculating reactance. You don't list other constraints on the circuit so I assume you just want to make R=xl=cl and you are not limited on the resistance values? I would round those values off to real world capacitors you can buy as standards if you plan to build it vs a theory exercise. in any case this will get you there I believe.

i know how to calculate those values manualy but only for simple series or paralar circuits, but in this example i have a mixed circuit and i'm not sure if i shuld calculate the total XC and make it equel to the XL in order to make resonance on the frequency 100 hrz

i don't think the resistance values makes any different
and i don't need real world capacitors
i just make this circuit in Orcad and simulate

i understand this formula, i just need to find values for the capacitor and inductor to get resonance on 100 mhz.

when L and C impedances match, (i.e. resonance), then the resistance becomes noting more than series resistance. The best thing to do will be to pick an arbitrary value and work the formula backwards solving for the missing component value. For example, setting a 10mH inductor would use a 10mF capacitor.

as you said i picked an arbitrary value for the inductor (L=10mH) and found the value of the capacitor to recive a resonance frequency at 100 hrz and i found that C=253.302uF

my calculations:
http://img593.imageshack.us/img593/8049/photo030212173055hdr.jpg

and i tried to place those value on the simulation program orcad pcspice
http://img94.imageshack.us/img94/286/42599051.jpg
only that i placed this values on both of the parts c1 and c2 l1 and l2

and i recived this:
http://img580.imageshack.us/img580/8971/63874598.jpg

is this the correct answer?
and is it possible to get two different resonance frequancy in one circuit such as this?
that the wave will be something like this?
http://img823.imageshack.us/img823/5848/11132918.jpg

O.k. formula is correct. and numbers work out as expected. the first formula is a little easier to work with though. 1/(2pi*(sqr(L*C))= resonant frequency. which can then be worked out to L*C=((1/(2*pi*100)^2) or L*C=2.53X10^-6 Then divide the number by L or C to find the opposite one. 2.53*10^-6/10mH = 2.53uF. It will make it easier to find the common value combinations without having to have special capacitor/inductor values.

The Resistance at that point does not affect the resonance.

thank you mike

and what about the second question?
is it possible to get two different resonance frequancy in one circuit such as this?
that the wave will be something like this?
http://img823.imageshack.us/img823/5848/11132918.jpg

What that looks like is a band-stop or band-reject filter. with a high and low pass filter to taper the outer edges.

An LC resonant filter is best for a notch filter, to allow a specific range through, because as frequency increase the inductor impedance increases. For frequency decrease, then the capacitor impedance increases. You might be able to work them to where the roll off of each section can provide something similar, but you will get a greatly reduced output from a given input.

one more thing
when i calculate the Q-factor i use the total resistence or from a specific resistor?
Q=(w0*L)/R

because each of the filters is "parallel", in that the capacitor and inductor are across from each other. the formula is a little different than the series formula. Parallel Q is

Q=R*SQR(C/L)

Series

Q=(1/R)*SQR(C/L)

what is SQR?
and shuld i use the total resistence or any specific one?