Voltage Representation

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#1 21667106 16 Mar 2013 06:12

ASAD ALI ASAD ALI

Anonymous

Post #1
21667106 16 Mar 2013 06:12

Could any one please explain me about the difference between these two equations???

Va(t)= Under Root (2)x Vm x sin (wt)

or Va(t)= Vm x Angle(0).
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#2 21667107 16 Mar 2013 06:40

Ulf Kirchner Ulf Kirchner

Anonymous

Post #2
21667107 16 Mar 2013 06:40

V(t) = sqrt(2) * Vm * sin(w*t) is the value of a sinusoidal voltage at time "t". Vm is the rms value of the sinusoidal voltage. the 2nd equation does not make any sense to me. (multiplying a voltage by an angel ????)
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#3 21667108 16 Mar 2013 06:50

ASAD ALI ASAD ALI

Anonymous

Post #3
21667108 16 Mar 2013 06:50

i have already got my answer sir,

the first one is a mathematical representation of instantaneous sine wave form and second one is actually a polar representation...
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#4 21667109 16 Mar 2013 06:58

Ulf Kirchner Ulf Kirchner

Anonymous

Post #4
21667109 16 Mar 2013 06:58

that means the 2nd formula should be read like V(t) = Vm * exp(j * w * t)
#5 21667110 15 Jun 2013 02:35

Dishan Pangan Dishan Pangan

Anonymous

Post #5
21667110 15 Jun 2013 02:35

V(t) = Vm * exp(j * w * t) is just the same as with Vm x Angle. Using Euler's formula in transforming polar to exponential (and vice versa), we can get the same result.
#6 21667111 15 Jun 2013 04:14

Ulf Kirchner Ulf Kirchner

Anonymous

Post #6
21667111 15 Jun 2013 04:14

@Pangan: its not the same, at least not for me. There is a diference between Angle and the sin(Angle) or cos(Angle). So again a Voltage multiplied by an Angle does not make any sense to me. If you use Euler then you get V(t)=Vm*(cos(w*t)+j*sin(w*t)) and not Vm times an Angle...
#7 21667112 15 Jun 2013 06:28

Donald Dahl Donald Dahl

Anonymous

Post #7
21667112 15 Jun 2013 06:28

I think by "Angle" he means the symbol for "cis" where cis(theta) = cos(theta) + j x sin(theta), so it should be written Va(t) = Vm x cis(wt)

see link: "http://www.intmath.com/complex-numbers/4-polar-form.php":http://www.intmath.com/complex-numbers/4-polar-form.php
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#8 21667113 15 Jun 2013 06:32

Donald Dahl Donald Dahl

Anonymous

Post #8
21667113 15 Jun 2013 06:32

Which is the same as what you wrote, Ulf...
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