First of all i want to mention that you can run that motor with VFD up to the motor's mechanical speed limit. But lf you are going to run a motor with vfd beyond its rated frequency ,motor would be in field weakening zone. Hence,the pullout torque and starting torque will be much more less. Beside that you did not mention the voltage level of 50hz motor. Assuming the same voltage level i amgoing to ellaborate the case by an example....
If the motor power is P , 50Hz, stg torque=Tst, Pull out torque= Tn
In 60Hz source, the speed would increase 1.2 times of the rated.
New flux level is 50/60 i.e 83%.
So the new power is P x 0.83 x 1.2 i.e P x .99
Wooosh !! Not a problem from power point of view.
But Tst~(50/60)^2 and Tn ~ (50/60)^2
It is clear that the value of Tst and Tn would be just 69% of original value at 50Hz. Both values are considering some tolerance as per the MEPS.
Hence, starting suitability needs to check up before connecting with the load.
However,if the rated voltage is 415, then the value of Tst and Tn would slightly increase.
