Dear Engineers and other Technical Experts,
I have a question I have been puzzling over for quite a while related to the distributed, or self capacitance of a winding of magnet wire.
First, take the case of a winding with a regular capacitor connected to both terminals of the winding. When a moving magnetic field in close proximity to the winding induces a voltage therein, the capacitor becomes charged and a current flows in the conductor while the capacitor is charging. While no current flows through the capacitor since the dielectric medium in the capacitor is an insulator, a current does flow through the conductor, producing a magnetic field in the winding. Correct me if I'm mistaken here.
Next, take the case of a winding with the leads not connected together, an open circuit. When a moving magnetic field nearby induces a voltage in the open winding, will this induced voltage result in the charging of the distributed capacitance within the winding, or must the winding leads be shorted (closed circuit) in order to charge the distributed capacitance?
And if the distributed capacitance of the winding can be charged with the winding open, does this produce a current in the open winding?
Any takers?
I have a question I have been puzzling over for quite a while related to the distributed, or self capacitance of a winding of magnet wire.
First, take the case of a winding with a regular capacitor connected to both terminals of the winding. When a moving magnetic field in close proximity to the winding induces a voltage therein, the capacitor becomes charged and a current flows in the conductor while the capacitor is charging. While no current flows through the capacitor since the dielectric medium in the capacitor is an insulator, a current does flow through the conductor, producing a magnetic field in the winding. Correct me if I'm mistaken here.
Next, take the case of a winding with the leads not connected together, an open circuit. When a moving magnetic field nearby induces a voltage in the open winding, will this induced voltage result in the charging of the distributed capacitance within the winding, or must the winding leads be shorted (closed circuit) in order to charge the distributed capacitance?
And if the distributed capacitance of the winding can be charged with the winding open, does this produce a current in the open winding?
Any takers?
