How to Design PI Controller for Buck Converter Using LM2743 and Bode Plot Analysis?

I'm final year student currently designing a buck converter with an analogue controller (LM2743). What my supervisor told me is to used a PI controller using bode plot. My design spec: 1. Vin=12V 2. Vout=5V 3. Pout=10Watt 4. Fsw=100KHZ From there I obtained my inductor (48.6uH), output capacitor (15uF) an load resistor at (2.5ohm). From there my transfer function is: 
From there I'm quite stuck on how to do it. Where I know the T.F for PI controller is Gc(s)=Kp+(ki/s). After that, lets say I've managed top design the PI controller. From datasheet LM2743, there are few components need to be connected to the main controller which is pin FB and EAO.
Its mentioned in the data sheet that the calculation can be made using the equation given but didn't tell on how to get the Fz1, Fz2, Fp1 and Fp2 where these value that can decide the components. 

Taufiq,
The first paragraph of your third attachment gives the clues you need for placement of  Fz1, Fz2, Fp1 and Fp2. You need to determine where the poles are in the design without compensation. that will tell you where the compensation zeros need to be. The compensation poles need to be set relative to the capacitor ESR and switching frequency.Best of luck

Taufiq,
I wrote an entire series of articles(right here on EEWeb) just for solving such a conundrum :Dhttps://www.eeweb.com/profile/sree-harsha-angara/articles
There are a couple of more parts after that but not so link friendly. I'd suggest glancing through these, I made them fairly math-light. 
Best