Will a Bulb Light Up or Short Circuit if Connected to Two Wires of the Same Phase?

When a bulb is connected to two wires of the same electrical phase and voltage, the voltage difference between these wires is zero, resulting in no current flow and the bulb not lighting up. This configuration does not cause a short circuit because both wires share the same potential at all times, moving synchronously through positive and negative half-cycles. The bulb requires a voltage difference between its terminals to allow current flow and illumination. Analogously, this is like two water tanks connected by a pipe and fed from the same source—no flow occurs between them due to equal pressure levels. If the bulb is connected with one wire from the phase and the other from a different phase or neutral, the bulb will light. Diagrams illustrating multiple wires connected to the bulb show that if two wires of the same phase are connected to the same terminal, closing a switch across them does not affect the bulb's state. Thus, powering a bulb from two wires of the same phase results in the bulb remaining off without causing a short circuit.
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