How to Test Diode and Capacitor Series Circuits In-Circuit With a Multimeter?

Hi everybody,


I'm looking for an easy and quick way to test diodes and capacitors in series without having to remove these from the circuit. I understand that just for a diode itself, we can use the diode function test and see what voltage it reads. For one direction, it should read between 0.3 - 0.6 V, and for the opposite direction it should read "OL". Is there a similar test for a combination of diodes and capacitors that are connected in series? I am having trouble determining this. Please refer to the pictures to see the two specific circuits that I am dealing with. Any advice would be greatly appreciated. Thanks in advance

Hi Vincent- I can't think of a practical way to do this.  If you apply DC voltage of one polarity to the series combination the diode will block it and nothing will happen.  If you apply DC voltage of the other polarity the diode will conduct until the capacitor is charged to the applied voltage and then it will look like an open circuit.  If you apply AC or a square wave to the circuit, the capacitor will charge to the peak value and then the series combination will look like an open circuit.I am curious- why do you have a short across the circuit in both of the examples you gave?-Rick . 

Hi Mr. Rick!
I think even if he applies DC voltage the other way, the diode will still not conduct because the other diode terminal is at high impedance. The enveloping diodes are forever floating components in my opinion.

i remember the day when i learn electronics in my university. this message was given by cheap reliable essay writing service as they essay provider so they have a great knowledge;
there is a simple way that  you can test diode is the resistance mode procedure is conducted as follow: 1. make action; off all the circuit that produces power and it's should be no voltage exist at the diode.2. connect the test leads to the diode after removed the circuit.3. reverse again the test leads.

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