Explaining Differences in Internal Resistance: Ammeter vs Voltmeter, Series & Parallel Connections

Hello, I have a task: Explain and justify the difference between the values of the internal resistance of the ammeter and the voltmeter.

I know that the voltmeter has a greater resistance because, by extending its range, we connect the resistors in series, and the ammeter is smaller because we connect the shunts in parallel. The problem is that I don't know if I'm thinking in the right direction and I can't put it all together.
I am asking someone to reply quickly

greetings

The resistance of the voltmeter should be as high as possible so that the meter itself does not overload the system being measured.
The low resistance of the voltmeter would make it impossible to measure the voltage. Digital meters have several megohms of internal resistance.
The opposite is true for the ammeter. We connect the ammeter in series to the circuit, so it must have the smallest possible resistance. If the ammeter had a high resistance, it would do it as a resistor connected to various places in the system. And such a system would stop working properly;]
The resistance of the ammeter is a few ohms maximum.

The voltmeter should have the greatest possible internal resistance in order not to load the voltage source and measure its electromotive force, not the electromotive force minus the voltage drop on its internal resistance caused by the current consumed by the voltmeter.

Perfect -> Rv = ?

The ammeter should have as little internal resistance as possible so as not to add additional resistance to the circuit, because this will change the actual value of the current in the circuit.

Perfect -> Ra = 0

Specimens and shunts only extend the ranges of the meters without changing the essence of the value range of these meters (of course, the tier increases Rv and the shunt reduces Ra)

in short, the voltmeter should have the highest possible resistance (ideal - infinitely great), for the reason that entering into the circuit should not load the circuit and thus change the voltage (lower)
ammeter the smallest possible resistance (ideally zero), similarly to the above, the resistance of the ammeter reduces the current flow through itself and changes the measurement
it is so in short