Hello, if I am writing in the wrong section then please move it. I heard that watts can be counted by multiplying volts * amps (12x420) and I came up with 5kW and 40W. Is this correct? Did I misrepresent something? Will it really pull that much?
Czy wolisz polską wersję strony elektroda?
Nie, dziękuję Przekieruj mnie tamaviva1 wrote:Approximately can, I understand that you substituted the allowable instantaneous battery discharge current.I heard that watts can be counted by multiplying volts * amps (12x420)
aviva1 wrote:12V x 420A = 5040 W or 5.04 kWI came up with 5kW and 40W. Is this correct? Did I misrepresent something?
Tommy82 wrote:With minutes I would be cautious, the maximum power will quickly start to drop. Practically there will never be 5kW because with a 420A load the battery will not hold 12V.The battery will only give you "so many watts" for a few minutes.
freebsd wrote:@aviva1 Well thought. More is described here: https://www.elektroda.pl/rtvforum/topic2027258.html