Arduino Leonardo stair lighting with motion sensors - how to write a sketch?

Hi. I have this question, I have decided to make a stair lighting based on arduino leonardo.
My problem is that I don't know much about it and I would like to get something like this so that by using motion sensors which, will give a signal and run a program in the arduino.
The sensors are located at the beginning of the stairs at the top and at the bottom, depending on the direction of exit the light will turn on from the bottom or from the top. My problem is that I don't know how to write a sketch to make the programme switch on the sensors.

And if someone comes in from below and above, what should happen?

I did not envisage this possibility, although it could light up from the top and bottom and meet in the middle.

Has anyone encountered such code on an arduino?

Hello buddy, I don't know if your topic is still relevant, but such installations can be easily realised with LOGO! 230R(C) controllers. You insert one sensor at the bottom, another one at the top, then you program the device in such a way that the lamps are switched on in sequence one after another using special function blocks (SF), e.g. ON DELAY, but for this you must first learn the basics of construction and operation of simple PLCs.

void setup() {
pinMode(13, OUTPUT);
pinMode(12, OUTPUT);
pinMode(11, OUTPUT);
pinMode(10, OUTPUT);

pinMode(1, INPUT_PULLUP);
pinMode(2, INPUT_PULLUP);

digitalWrite(13, LOW); /Disabling the LEDs
digitalWrite(12, LOW);
digitalWrite(11, LOW);
digitalWrite(10, LOW);
}

void loop()
{


delay(1000); //Stop the program before entering the loop for 1 second
while (digitalRead(1) == HIGH) {} //If the button is pressed

digitalWrite(13, HIGH);
delay(1000);
digitalWrite(12, HIGH);
delay(1000);
digitalWrite(11, HIGH);
delay(1000);
digitalWrite(10, HIGH);

delay(3000);

digitalWrite(13, LOW);
delay(1000);
digitalWrite(12, LOW);
delay(1000);
digitalWrite(11, LOW);
delay(1000);
digitalWrite(10, LOW);

delay(1000); //Stop the program before entering the loop for 1 second
while (digitalRead(2) == HIGH) {} //If the button is pressed

digitalWrite(10, HIGH);
delay(1000);
digitalWrite(11, HIGH);
delay(1000);
digitalWrite(12, HIGH);
delay(1000);
digitalWrite(13, HIGH);

delay(3000);

digitalWrite(10, LOW);
delay(1000);
digitalWrite(11, LOW);
delay(1000);
digitalWrite(12, LOW);
delay(1000);
digitalWrite(13, LOW);
}

I have used two buttons only I don't know how to break the loop.
After pressing the first button (e.g. at the bottom) I have to press button two (at the top) to make the first button work again