Stainless Steel Rod Bending Strength for fi 10mm & fi 8mm, 5cm Protruding, 10cm Embedded in Wall

Hello, I need to list such a thing. A steel rod "fi" 10mm protrudes from the concrete wall, the protruding part of the rod is 5cm. The question is: how many kilograms can you hang at the end of the rod so that it does not bend? Please also solve the same problems for the rod diameter "fi" 8mm and the same length of the rod 5cm protruding from the wall. The part embedded in the concrete wall is 10cm in both cases. Until tomorrow to solve the problem Thank you very much for your help and let me add that I cannot calculate it myself, so please do not give me the formulas because they will not help me.

The rod is to be of the best stainless steel I can get, it will be sunk a lot of time in the water and it must be of some good stainless steel. It will be a smooth or threaded rod.

The load will be dynamic.

The rod is not supposed to bend, it is bent, there is no way it has to be "stuck" ;-)

I would like to add that this is not a school task I have to do some fastening in this way and I do not want to do it wrong so I need this information.

The steel grade is A2.

Bump or pervert. Yield strength I mean. Static, dynamic load? Security limits? You didn't write much about important topics.

This is probably also where the rod is made of, what the steel is made of. If they did not specify in the task, say that it cannot be solved because the steel was uneven and you did not do the lack of data.

I adopted a typical grooved reinforcement. But in fact, it is not known how smooth or grooved the material is.

kkknc wrote:

I adopted a typical grooved reinforcement. But in fact, it is not known how the material is smooth or grooved.

Any chance of calculating this?

You can, but you must specify exactly what BSt500 or 34GS steel and what was written above. The main types of armor are steel.

Today I called the company where I buy steel and they told me that they have A2 and A4 steel, I don't know what's going on but I choose the better one. Is there anyone here who can calculate it?

https://www.art-nierdzewne.pl/content/7-o-stali-a2-a4
http://www.stalenierdzewne.pl/porady-ekperta/...%B3%C5%BCnica-mi%C4%99dzy-stal%C4%85-typu-a2- a4-i-302304316-same-steel-only-ina
Here you have the difference between A2 and A4 steel, so the easiest way is A4 is more chemically resistant than A2. A2 steel is called "stainless" and A4 "acid-resistant".

Robinson wrote:

The rod is to be the best stainless steel I can get

Robinson wrote:

Today I called the company where I buy steel and they told me that they have A2 and A4 steel, I don't know what's going on but I choose the better one.

This is more related to chemical resistance than strength. I have a book on metallurgy with described steels, strengths, etc., I can look and see which one is the most durable and resistant to your conditions, just specify exactly how this bar will be loaded and under what conditions it will work.
I just don't know if it will be easily available, we can find some great steel, but what if you can't buy it anywhere. Maybe it's better to just oversize the rod properly?

supchem wrote:

https://www.art-nierdzewne.pl/content/7-o-stali-a2-a4
http://www.stalenierdzewne.pl/porady-ekperta/...%B3%C5%BCnica-mi%C4%99dzy-stal%C4%85-typu-a2- a4-i-302304316-same-steel-only-ina
Here you have the difference between A2 and A4 steel, so the easiest way is A4 is more chemically resistant than A2. A2 steel is called "stainless" and A4 "acid-resistant".

Robinson wrote:

The rod is to be the best stainless steel I can get

Robinson wrote:

Today I called the company where I buy steel and they told me that they have A2 and A4 steel, I don't know what's going on but I choose the better one.

This is more related to chemical resistance than strength. I have a book on metallurgy with described steels, strengths, etc., I can look and see which one is the most durable and resistant to your conditions, just specify exactly how this bar will be loaded and under what conditions it will work.
I just don't know if it will be easily available, we can find some great steel, but what if you can't buy it anywhere. Maybe it's better to just oversize the rod properly?

It's all cool, it's easy to oversize, but how much? After all, to oversize, I need to know how much such a bar as I mentioned in the first post will withstand, and then give it a thicker one. Damn everyone I see wants to help but everyone asks only a million questions, and rivet can't solve a simple task including me :cry:

Can someone solve this task and give a specific answer? All parameters are described at the beginning of the topic.

Hello. Nobody will give you a simple answer because you have given too little data. The mere fact that you do not care whether the rod is threaded or not changes its bending strength. Nobody will conjure the result from the ball. Read more into the topic to ask specific questions, not generalities. Regards

Count for yourself, below


I post the necessary patterns. For Wz, put ?d to the 3/32 power.

The same units are newton (N) and meter. For steel, the coefficient kgj is approximately 0.05-0.45 Re (Re yield point).
Enter the bending moment in Nm, i.e. 1 kg of the load is 10N, and the arm of the force, i.e. from the wall to the point of the load.
The result will be in N, divide by a million and you will get in MPa, compare if the strength condition is met and that's it.

correction: kgj = 0.35-0.45 Re

You know, you wrote that the sticking out rod should stand still. Believe me, it doesn't take much strength to get beaten. It is true that if you do not exceed the yield point, the bar will return to its previous state without deformation, but it will bend nevertheless. You also did not provide the distribution of forces. Otherwise, you calculate the force at the block itself, where you basically have shear, and otherwise how you apply the force at the very end, and you care about changing the coefficients as the load is even. Say what you want to do and why it will be easier.
See how many patterns you have on this page and what load you anticipate.
http://www.naukowiec.org/wzory/inzynieria/nos...ój-przy-zginaniu-jednokierunniczego_2557.html
Look at the footer at the bottom.
Now do you know what problem we are talking about?
And that it is not that simple.

Hehe why do you want rebar in this structure, just apply a wall holder and fix it with wall plugs.

At 5 cm the rod 10 bends visibly already at 10 kg suspended at the end.
TO permanent deformation I don't know.


And you can see for yourself what makes designers different from Lajkoników. You need a lot of data for calculations.

Robinson wrote:

The bar is to be of the best stainless steel I can get, it will be sunk a lot of time in the water and it must be of some good stainless steel.

supchem wrote:

just specify exactly how this bar will be loaded and under what conditions it will work.

Robinson wrote:

Damn everyone I see wants to help but everyone only asks a million questions

Or maybe it's not everyone who asks a million questions that do not help you at all, but you just don't know too well how to choose the material?
You see the rod is supposed to be in the water, but how salty or sweet, what pH? Stainless steel is not like it does not rust at all. For example, concrete, before it solidifies, seems to be alkaline with a pH of about 10-11 (I don't remember exactly).
If you would know what I mean, I am referring to a fragment of Mr. Leon Mistur's book entitled Gas and electric welding.

OH12 and OH13J steel, resistant to atmospheric corrosion, natural water and steam, type - stainless.
OH17T steel - resistant as above and to hot crude oil vapors, diluted alkaline solutions at boiling point.
Steel OH18N9, 1H18N9, 2H18N9, OOH18N10, 1H18N9T, resistant as above and
- inorganic acids with the exception of hydrochloric, sulfuric, nitric acids, bromine and chlorine
- organic acids
- lactic and oxalic acid
- salt solutions
- all food products
Will this bar be welded to the reinforcement? (also of stainless steel) The steels I mentioned here are stainless steels used for welded parts.
First, you need to precisely define the conditions under which the element works. Let's say chemical and physical conditions, i.e. in what water, temperature, etc., you need to consider whether the element will be welded to something or not, whether it will be threaded, bent, etc., you will have a group of steel that you can use, then you have to choose the strength of them. the type of steel and the thickness of the element, it is also necessary to take into account the economic issue and the availability of the steel.
Why do you want to use "the best" stainless steel, or do you want the highest possible strength to be able to use a thinner element? Does it have to be small for some reason?

Strumien swiadomosci swia wrote:

Hehe why do you want rebar in this structure, just apply a wall mount and fix it with wall plugs.

At 5 cm the rod 10 bends visibly already at 10 kg suspended at the end.
I don't know for permanent deformation.


And you can see for yourself what makes designers different from Lajkoników. You need a lot of data for calculations.

I know I can't calculate it. I called a few people who were graduating from construction studies. Nobody could count it. I gave all the data for calculations, so please do not write that you need a lot of data. None of you can calculate it, nor do I think that there is no point in continuing it because there will be more questions that will lead you to nothing

Robinson wrote:

None of you can calculate it

I can assure you that if you specified what steel and how it is loaded (at the end, at the beginning, etc.), someone would charge you. It cannot be done with your data. You can load it from above with a metal beam next to the wall and then we will consider shear, maybe at the very end and we have bending, etc.

Robinson wrote:

I have provided all the data for calculations

But don't you understand that such a rod will always bend ...?

Acid-resistant stainless rod: diameter ?10 mm
Weight: 1 m = 0.62 kg
Grade: 1.4301 / 0H18N9 / 304 yield strength 230 MPa
For steel, the permissible cyclic bending stress is kgj = 0.35-0.45 Re
I take 0.35 x230 MPa = 80.5 MPa
For this condition to be met, a load of no more than 19,200 N = 19.2 kN = 1,920 kg at the end may be suspended

8.15 e-4 meters

The phone is not very precise.
The deflection of 0.000 815 is not almost a centimeter.

Thank you for all your help. Especially the "smartest". No comment. It is a pity for my writing, because if I give all the data, there will be someone wise who will write that I did not give the ambient temperature.