Lenovo - Lenovo power supply - flat plug with PIN and resistor. What?

Question

Hello,

I have a power supply in which I need to replace the cable (with a flat 11x4.2mm plug)
There is a control PIN in this cable. For the 65W power supply it is 285 ?, for the 90W it is 548 ?. And what should the 45W power supply be like?
And what will happen if a 584 ? resistor is used for the 45W power supply ??

boro1234567 · Answer

Nothing wrong.

Jack78 · Answer

But will the power supply be correctly recognized and whether the charging will proceed correctly.

boro1234567 · Answer

Should not. I have 560? in the service cable and all boards work without any problems.

slawmix1234 · Answer

One question, where do you want to solder this resistor? , we are talking about a cable with a flat plug that looks like a usb from a mouse, out of curiosity I checked the factory cable has two wires + and -
, and between the negative and the pin the resistance measurement gave a result of 298Ohm, between the + and the pin there is a break

Jack78 · Answer

There is a resistor embedded in this plug.

slawmix1234 · Answer

So what's the problem?

Jack78 · Answer

I wanted to know what is in 45w power supplies

codiql · Answer

Hello
I had a Lenovo G50-30 with an ADLX45NCC3A power supply on the table.
Measurement between Ground and Signal pin gave 120 Ohm.
Due to the lack of lacquer, I used a 100 Ohm resistor and the charging worked properly, i.e. 1.2A - 1.4A with the Win8.1 desktop and 0.847A at 20V with the laptop turned off.
However, without a 0.012A battery when turned off and 0.4 - 0.6A at the panel.

I recommend post # 6 from the address http://cafealle.pl/c/index.php?topic=183.0
Listed below:
Measurement between V- and Signal internal pin
20V / 2.25A 45W - 0.12k?
20V / 3.25A 65W - 0.263k?
20V / 3.5A 70W - 0.267k?
20V / 4.5A 90W - 0.555k?
20V / 6.75A 135W - 1.504k?

R_3_M · Answer

gentlemen,
Whether from the Lenovo power supply: 20V / 6.75A 135W - 1.504k?
you can make a power supply for HP, which has the voltage levels between the outer (mass) and inner cladding is 19.9 - 20V and between the inner cladding and the pin about 15.5V.
Can you drop by, which is the easiest way to do it?

Stani12 · Answer

You need to replace the wire, it will have a round large / small plug. The middle pin in the power supply must be connected through a resistor of approx. 300k / for 65W / to + 19V. / remember not to connect to this point which is for Lenovo because it is connected via a low resistor to the gnd. / Enter what hp laptop, I will give more detailed resistor data.

R_3_M · Answer

I already bought the cable (it rushes to me with a parcel locker

.
The exact laptop model for the HP G62. Nominally there is a 65W power supply for it, but I want to make it more powerful. Since I have an unused ~ 120W power supply for Lenovo, an idea was born to use it.

I understand your information as shown in the image below:

The question remains: what should be the value of the resistor "R"?

Stani12 · Answer

This is exactly how it needs to be done.
With a 90W power supply, the resistor should be 330k.
With a 120W power supply, a 120k resistor.
Don't use god's fortune on Dell-i. One wire systems are programmed in Dells. They generate waveforms that the computer recognizes. The pulse bundle is power dependent.
The amplitude of the signals is 5Vss. If the HP power supply is given to the center pin, this pin will be 19V, so it will release the identification system.

Lenovo - Lenovo power supply - flat plug with PIN and resistor. What?

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