Hello, dear group of professionals.
Recently, a colleague from work asked me to take a look at his electrical installation in England. I defended myself against this for a long time because I do not have the appropriate knowledge and documents. After some time, hearing from my friend that the electrician had left him a plan on the wall on how to connect the wires and the friend was sure he knew how to connect "plus and minus", as he put it, I decided that I would take a look at it. I removed and secured some old wires hanging from the walls, which, surprisingly, were under voltage and there were three small children in the house. Later, I had to use one cable to connect to the switchboard, because that was all he asked me to do :P
So, TN-S type installation, single-phase installation, WLZ 25mm, Pe cable connected to the house together with N and L, i.e. no PEN distribution in the house. The rest is as in the photos.
Note: the photos were taken after the intervention of "Master Kowalski" of everything - bricklayer, plasterer, acrobat """ visible blue colors of wires connected to overcurrent fuses, I had the opportunity to see the installations of the first Alfa specialist.
An interesting thing caught my eye, there is an output in the fuse with two wires - circlut line,
i.e. the L wire goes to the first socket, from this to the second, etc. and from the last socket in the circuit, the L wire runs back to the switchboard and is connected to the same fuse. So I scratched my head a bit and on the one hand it makes sense, because if there is a break in the circuit, e.g. between the first socket and the second one on the L wire, we still have voltage on the second, third, etc.
However, the problem is with the size of the protection, which I do not understand and I am asking for clarification, because the wires are 2.5 mm and the fuse is 32 A.
In my opinion, the security should be 16 A. [without calculating from formulas, etc.].
I asked my friend to call and ask if the Alfa electrician hadn`t made a mistake, but Alfa said that twice 2.5 mm is equal to 5 mm, so it`s a kind of protection.
I don`t like it a bit, because what if there is a break in the circuit, e.g. between the fuse and the first socket, and someone decides to connect two stoves and a kettle? A current of e.g. 30 A will then flow, and the long-term load capacity of Cu 2.5 mm is about 16 A. Moreover, it is the same circuit, so where is Kirchhoff`s first law here?
I would like you to explain this, because in my opinion it is a mistake.
Recently, a colleague from work asked me to take a look at his electrical installation in England. I defended myself against this for a long time because I do not have the appropriate knowledge and documents. After some time, hearing from my friend that the electrician had left him a plan on the wall on how to connect the wires and the friend was sure he knew how to connect "plus and minus", as he put it, I decided that I would take a look at it. I removed and secured some old wires hanging from the walls, which, surprisingly, were under voltage and there were three small children in the house. Later, I had to use one cable to connect to the switchboard, because that was all he asked me to do :P
So, TN-S type installation, single-phase installation, WLZ 25mm, Pe cable connected to the house together with N and L, i.e. no PEN distribution in the house. The rest is as in the photos.
Note: the photos were taken after the intervention of "Master Kowalski" of everything - bricklayer, plasterer, acrobat """ visible blue colors of wires connected to overcurrent fuses, I had the opportunity to see the installations of the first Alfa specialist.
An interesting thing caught my eye, there is an output in the fuse with two wires - circlut line,
i.e. the L wire goes to the first socket, from this to the second, etc. and from the last socket in the circuit, the L wire runs back to the switchboard and is connected to the same fuse. So I scratched my head a bit and on the one hand it makes sense, because if there is a break in the circuit, e.g. between the first socket and the second one on the L wire, we still have voltage on the second, third, etc.
However, the problem is with the size of the protection, which I do not understand and I am asking for clarification, because the wires are 2.5 mm and the fuse is 32 A.
In my opinion, the security should be 16 A. [without calculating from formulas, etc.].
I asked my friend to call and ask if the Alfa electrician hadn`t made a mistake, but Alfa said that twice 2.5 mm is equal to 5 mm, so it`s a kind of protection.
I don`t like it a bit, because what if there is a break in the circuit, e.g. between the fuse and the first socket, and someone decides to connect two stoves and a kettle? A current of e.g. 30 A will then flow, and the long-term load capacity of Cu 2.5 mm is about 16 A. Moreover, it is the same circuit, so where is Kirchhoff`s first law here?
I would like you to explain this, because in my opinion it is a mistake.
I wanted to check my own way of thinking.
