Power consumption by a computer

I would like to know how much power the computer uses at 10-12 hours a day and how much it will amount to a month.

Processor: Intel Intel Core i5-7400 /3.0GHz, 6MB, BOX
Motherboard: AsRock AsRock H110M-HDV R3.0
Memory: GoodRam GoodRam 16GB (2x8GB)
HDD: Western Digital Western Digital Blue 1TB
SSD: A-Data A-Data SP920 128GB SATA3
Power supply: Corsair Corsair CX450M 450W
Graphics card: Gainward Gainward GeForce GTX1060 Phoenix 6GB DDR5 192bit (1708/8000)
Monitor: Samsung SyncMaster B2230H

Buy a wattmeter. They are so to the outlet. There is no other method because it basically depends on what the computer counts for 12 hours, how often and how intensely. You can estimate something there, but in this case, we will rather guess the order of magnitude than any value.
As for costs - the power consumption in kWh is multiplied by the value of 1kWh plus variable costs and this value can be found on the electricity bill (also not constant and equal for everyone, depending on the location, supplier and tariff).

310artur wrote:

Buy a wattmeter. They are so to the outlet.

Maybe not so much as the watt meter, but the "energy meter" you enter in google, you will immediately see what's going on.
I bought my big damn for 39.99 or 49.99 zlotych a few years ago, which covers 2 sockets so you have to take this into account when you buy, if you have sockets on the contact.
And the best thing about it is that you do not have to count anything, you only need to know what rate you have for kWh, if you remember my memory in Tauron tariff G11 is 0.61gr / kWh, you enter into this system and he already gives you the final the amount to be paid for "used / collected" energy.

My 7-year-old computer, consumes about 90W, laptop 2/3 of this power, about 60W.

Assume that in Idle this set gets ~ 100W, and when loaded (eg: game) ~ 200W.

Jeziera95 wrote:

Power supply: Corsair Corsair CX450M 450W

Gentlemen, maybe I'm wrong but it is not like this: 450W X 1h = 0.45kWh and with ten hours of work this set will come out: 0.45kWh X 10. I know that these 450W is the maximum current efficiency of this power supply.

gumisie wrote:

I might be wrong

You're probably wrong. Yes it does not work. First of all, the maximum power of the power supply is usually on the secondary side, so the maximum power consumption from the socket is bigger (it has to be divided by efficiency). Secondly, a computer like any device will take as much energy as it needs. It's a bit more complex device than a light bulb but I assure you that if you plug a 10W bulb (eg car on 12V) into such a power supply, it will not explode and the power supply from the outlet will download a little over 10W (11-12W)

and without buying a watt-meter you can deal with it. You disconnect everything at home, except for the computer, you play for example: 2 hours (the freezer will not be thawed). By subtracting the energy meter display after turning off everything from the current consumption, you divide these two hours and get satisfactory information. This method combines possible failures in the energy meter itself.

310artur wrote:

the power supply from the outlet will download a little over 10W (11-12W)

So that's how much? Wh is the unit of energy consumption. Considering 90% efficiency of the power supply + 10W load. They will be Watty or Wh.

11.1 Wh (0,011kWh) will be used within one hour.
We will not discuss integrals and differentials that's how it works. In total, it is worth knowing what you are paying for

PS in engineering practice, the cost of energy is calculated by dividing the size of the bill by energy consumption (in simplified terms, but that makes sense - it counts "forward"). At home, it has little sense but in industry it has. The higher the consumption, the smaller the influence of fixed components on the kWh price. At home, this is the easiest way to calculate the real cost of energy. It can be counted on the basis of the account for the previous period. And just wanting to calculate how much the bill will increase, only the price of kWh and variable components should be taken into account (they are impressed in PLN / kWh, e.g. transmission)

Completely theoretical:
At rest (browsing the internet, working in a text editor) such a computer (without a monitor) gets about 50W. More or less (53-60W) models with overclocked i7-6700K and GTX1060 have been downloaded, so you can safely assume that the version with an untwisted processor of the newer generation should fit in around 50W.

Under full load, this machine took 200W, but the overclocked I7-6700K probably takes a little more than the I5-7400.

Measurements were already made from the socket, so the efficiency of the power supply does not need to be taken into account.

10 working hours times 50W = 500Wh = 0.5kWh (no load)
10 working hours, 200W = 2000Wh = 2kWh (full load)

The full-load value is pessimistic, even if the game does not persist permanently.

I do not know how much in your tariff costs 1kWh, but playing 10 hours you will use something between 1 and 2kWh of energy, and looking at the pages probably about 0.5kWh.

If you want to get more accurate results - the previously recommended measuring device will give you more accurate answers.

Add another monitor because it's another 40-50W.

That's why I wrote:

Kasek21 wrote:

Assume that in Idle this set gets ~ 100W, and when loaded (eg: game) ~ 200W.

You connect a universal meter and measure the current drawn from the network. you calculate
P = U * I
You have more or less power from the network.

szkieletor11111 wrote:

You connect a universal meter and measure the current drawn from the network. you calculate
P = U * I
You have more or less electricity drawn from the network.

It is very difficult to do this in such a way because the current consumption of the computer is not constant, it varies depending on the load. It will be difficult to consider the results calculated from one instantaneous measurement reliable.

szkieletor11111 wrote:

You connect a universal meter and measure the current drawn from the network. you calculate
P = U * I
You have more or less power from the network.

Measurement completely nonsensical.

I would add an audio amplifier and what else is there around the computer. The easiest way to read from your electricity meter is consumption in a longer unit of time. This is the most authoritative way to estimate the labor costs of a computer set.

deksta84 wrote:

This is the most authoritative way to estimate the labor costs of a computer set.

The most reliable is the wattmeter.

The problem is different to accurately estimate the consumption - because it is not constant in a unit of time; for this, looking at the monthly settlement will always be different because the computer is used to varying degrees.

This is a new computer - there are tests what is the power consumption so I will repeat:

Kasek21 wrote:

Assume that in Idle this set gets ~ 100W, and when loaded (eg: game) ~ 200W.

Wattmeter what type? It has been found (which is true) that the computer set is loading the network. The wattmeter measures the instantaneous power consumed. How is it for real wear, eg daily diurnal?

Same problem in this topic:
link

Enter a watt meter for allegro - that's what they say, but these are energy meters. They integrate over time, some even give wonders wreaths like CO2 emissions So you have, for example, the sum of energy consumed during 10 hours. There is still an open question, what is the frequency of measurement, but it is already enough to estimate the consumption - you plug the list into the socket for this and for example, you count the week. You divide multiply and you have an average of an hour exactly enough even in the case of an unevenly loaded PC.