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Cross-section and diameter of the cable. Diameter 2.5mm into mm

Matikqw 63786 22
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Treść została przetłumaczona polish » english Zobacz oryginalną wersję tematu
  • #1 18615067
    Matikqw
    Level 3  
    I would like to know if I am calculating the cross-section of the cable correctly.
    I have a cable with a diameter of 2.5mm (measured wire without insulation).
    I substitute it into the formula for the area of a circle, and the cross section comes out?
    P= 3.14xdiameter? ?
    P=3.14x2.5x2.5
    P=19.6mm?

    Is that how it's measured?
    I have doubts because the cable seems too thin for me to use.
    What is the safe strength of such a cable?
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  • #2 18615084
    kkas12
    Level 43  
    The formula for the area of a circle:
    P = ? o r2
    Question:
    what is "r"???
  • #3 18615113
    awow
    Level 12  
    The cross-sectional area of the conductor, for a diameter of 2.5mm, is 4.91mm?. It should be added that the diameters of the wires are standardized and the closest are 4 or 6mm?.
  • #4 18615124
    Matikqw
    Level 3  
    Oh right. Stupid mistake. It's a quick calculation. So thanks thanks.
    And if I have it 4.91, I round it to 4mm?? It's begging for 5mm? more
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  • #5 18615126
    DiZMar
    Level 43  
    S = ?r? = ?(d/2)?. Where
    S - area in mm?,
    ? - 3.14
    r - radius in mm
    d - diameter in mm
    For you, d = 2.5, so the area S = 3.14 x 1.25? = 4.91 mm?. That's the whole philosophy.
  • #6 18615165
    kkas12
    Level 43  
    DiZMar wrote:
    4.91mm?
    Is there such a cable?
  • #7 18615188
    jurek849
    Level 17  
    You're doing it wrong, the formula for the area of a circle is 3.14 x r squared, which is 3.14 x 1.25 x 1.25 = 4.9 mm?. The current density depends on the material of the cable, /copper or aluminum/ and the type of device, type of load.
  • #8 18615247
    slawekx
    Level 29  
    The formula for the area of a circle is:

    P=?r?

    Explanation of symbols:

    P - area of the circle

    r - radius of the circle

    A circle with center O and radius r (r > 0) is the set of points in the plane whose distances from O are less than or equal to r.
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  • #9 18615298
    DiZMar
    Level 43  
    kkas12 wrote:
    DiZMar wrote:
    4.91mm?
    Is there such a cable?

    Calculated on the basis of the topic author's data. The fact that there is no such cable does not mean that the author of the topic should not be led out of the wrong calculation based on the data provided by him. Probably his diameter is 2.256 mm and not 2.5 mm, and then a wire with a cross-section of 4 mm? or 2.764 mm and a cross-section of 6 mm?. Or maybe he invented these 2.5 mm in diameter? He supposedly wrote that the cable measured without insulation. I wonder what he measured? Maybe a ruler with a scale with an accuracy of 1 mm? He assessed these 0.5 mm "by eye".
  • #10 18615332
    Rasel
    Level 22  
    kkas12 wrote:
    DiZMar wrote:
    4.91mm?
    Is there such a cable?


    Maybe it's winding wire? There is such a copper wire with a diameter of 2.5 mm.
  • #11 18615342
    DiZMar
    Level 43  
    Rasel wrote:
    kkas12 wrote:
    DiZMar wrote:
    4.91mm?
    Is there such a cable?


    Maybe it's winding wire? There is such a copper wire with a diameter of 2.5 mm.

    And there's the answer. I admit I didn't know about it.
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  • #12 18615360
    kkas12
    Level 43  
    You know what measurement such calculations. As a result, neither one nor the other is worth anything.
    And even if junior high school exams are postponed, it doesn't mean that you can't apply the formula for calculating the area of a circle by putting an equal sign between the diameter and the radius.


    From the title of the thread, it does not appear that the author had winding wire in mind.
  • #13 18615379
    DiZMar
    Level 43  
    kkas12 wrote:
    You know what measurement such calculations. As a result, neither one nor the other is worth anything.
    And even if junior high school exams are postponed, it doesn't mean that you can't apply the formula for calculating the area of a circle by putting an equal sign between the diameter and the radius.


    The title of the thread does not indicate that the author had winding wire in mind.

    You sound like a politician. A specific question and he talks about side topics all the time he spends on it.
  • #14 18615524
    kkas12
    Level 43  
    The whole thread only shows that neither the measurement nor the calculations were done correctly.
    In the case of measurement, inaccuracy and in the case of calculations, words are missing.
    And it's in the professional section.
  • #15 18615778
    Matikqw
    Level 3  
    kkas12 wrote:
    The whole thread only shows that neither the measurement nor the calculations were done correctly.
    In the case of measurement, inaccuracy and in the case of calculations, words are missing.
    And it's in the professional section.


    Today, I quickly measured with a caliper, but it was definitely closer to 2.5mm. I will measure again to clear my doubts.

    If you write that the calculation is wrong, please do it right, because I don't understand where the error is (of course not in my calculations, but in other users' calculations)
  • #16 18615963
    kkas12
    Level 43  
    If diameter and radius are the same for you, congratulations on your uncritical approach.
    And a nonchalant approach to measurement results in an incorrect result of my friend's calculations, which can be seen from their result, because a wire with such a cross-section does not exist.
  • #17 18616018
    Matikqw
    Level 3  
    I know it's not the same. I do not deal with this on a daily basis and I approached the calculations quickly, so it's my stupid mistake, which I admitted earlier. So much. I'll measure the diameter tomorrow and let you know.
  • #18 18616290
    Rafael22
    Level 21  
    A little cheat for posterity
    Cross-section and diameter of the cable. Diameter 2.5mm into mm
  • #19 18616327
    CYRUS2
    Level 43  
    Matikqw wrote:
    I have a cable with a diameter of 2.5mm (measured wire without insulation).
    Depends on what the author is measuring.
    Doubtful that I micrometer.
    If the measurement result is 2.4 instead of 2.5, the calculated cross-section is 4.32mm?.

    The cross-section is not important, only the resistance of the length of the conductor.
    I measured it.
    In many cases, the resistance was lower than it appears from the declared cross-section.
    Declared - the measurement error of the cross-sectional area is eliminated.
  • #20 18616342
    DiZMar
    Level 43  
    CYRUS2 wrote:
    ...
    In many cases, the resistance was lower than it appears from the declared cross-section.
    ...

    Maybe the copper was of a higher quality than expected or the cross-section was with a positive tolerance? So he led better than the parameters give. There was no danger, because the project, even in nominal acceptable values, was becoming a margin. Usually the declaration is better than the reality. Here reality is better than declaration.
  • #21 19019988
    pejan 123
    Level 9  
    I am still asking for help in determining the cross-section of the cable at the connection to the house.
    The cable is aluminum 4x? but its cross-section is close to a triangle. I measured with a caliper and it is about 4mm at the widest point.
    Will it be something around 4x10 or maybe due to the triangular shape not round it will be 4x16?
  • #22 19020287
    krzysiek7
    Moderator of Electricians group
    Personally, I have never come across a 10 mm square sector, and 16 definitely. If the connection was made not long ago, 10 is not realistic. For many years, the minimum cross-section of an AL conductor has been 16 square mm.
  • #23 19020303
    pejan 123
    Level 9  
    krzysiek7 wrote:
    Personally, I have never come across a 10 mm square sector, and 16 definitely. If the connection was made not long ago, 10 is not realistic. For many years, the minimum cross-section of an AL conductor has been 16 square mm.


    I thought so too. This is good news for me. Thanks.

Topic summary

The discussion revolves around the calculation of the cross-sectional area of a cable with a diameter of 2.5mm. The correct formula for the area of a circle is emphasized as P = πr², where r is the radius (1.25mm for a 2.5mm diameter). The calculated cross-sectional area is approximately 4.91mm². Participants express concerns about the accuracy of the diameter measurement and the existence of a cable with such specifications. The importance of measuring tools and the material of the cable (copper or aluminum) in determining current capacity and resistance is also highlighted. Some users question the validity of the measurements and calculations, suggesting that the diameter might be misreported or that the cable type may not exist.
Summary generated by the language model.
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