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Calculating Wire Cross-Section from Diameter, Length, and Resistance Formula

lucasek 76765 9
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Treść została przetłumaczona polish » english Zobacz oryginalną wersję tematu
  • #1 3851463
    lucasek
    Level 2  
    How can I calculate the cross-section of a conductor based on diameter, length and resistance ??? Is there a formula I can use to calculate something like this?
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  • #2 3851536
    WojtasJD
    Level 43  
    As for the cross-sectional area, it can be calculated knowing only the diameters: (? * d ^ 2) / 4
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  • #3 3851561
    elek555
    Level 37  
    Look at the patterns from the primary school for the area of the figures you have visible as the cross-section of the wire. Use the measuring cup and count S.
    For a circular cross-section S = 0.25?d?, ??3.14 d-wire diameter
    And connect the resistance with the formulas R = ?l: S, ?-resistivity from the tables l-length
  • #4 3851601
    lucasek
    Level 2  
    Well, so much that substituting these patterns for the result has nothing to do with the one given in the tables.

    Added after 7 [minutes]:

    for example, with a steel wire diameter of 1.43mm and a resistance of 4287.3 Ohm, a length of 1m ... the resistive result is in the order of 14042.66 ... while the table shows that it should be 0.027 * 10 ^ (- 6) !!!

    Added after 16 [seconds]:

    What am I doing wrong ????
  • #5 3851828
    BolzZ
    Level 26  
    hmm, but you asked how to count the wire cross-section and you count the conductor resistivity :D
  • #6 3851948
    WojtasJD
    Level 43  
    lucasek wrote:

    for example, with a steel wire diameter of 1.43mm and a resistance of 4287.3 Ohm, a length of 1m ... the resistive result is in the order of 14042.66 ... while the table shows that it should be 0.027 * 10 ^ (- 6) !!!


    d = 1.43mm
    R = 4287.3 ?
    l = 1m

    ? = R * S / l = 4287.3? * (1/4 * ? * (1.43mm ^ 2)) / 1m = ~ 6.886 * 10 ^ (- 3) ?m

    The resistance of this cable is quite high, besides, it is not known what steel, what temperature.
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  • #7 3852216
    Quarz
    Level 43  
    Hello,
    WojtasJD wrote:
    lucasek wrote:

    for example, with a steel wire diameter of 1.43mm and a resistance of 4287.3 Ohm, a length of 1m ... the resistive result is in the order of 14042.66 ... while the table shows that it should be 0.027 * 10 ^ (- 6) !!!


    d = 1.43mm
    R = 4287.3 ?
    l = 1m

    ? = R * S / l = 4287.3? * (1/4 * ? * (1.43mm ^ 2)) / 1m = ~ 6.886 * 10 ^ (- 3) ?m

    Spore resistance of this cable, besides, it is not known what steel, what temperature.

    if it's not resistance, only resistivity , i.e. the material constant, and this is the fundamental difference.
    After all, you have calculated ? = 4,287.3 o 3.14159 o (1.43 / 2000) ^ 2/1 = 6.885658E-0003 ? o m

    greetings
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  • #8 3852237
    WojtasJD
    Level 43  
    :arrow: Quarz

    I know what I have calculated :wink: and I wrote it well - I wrote (or actually commented) about _resistance_ R = 4287.3? given earlier by col. lucasek (because a 1m steel wire with a diameter of 1.43mm with over 4k? is a bit much ...)
  • #9 3852264
    Quarz
    Level 43  
    Hello,
    WojtasJD wrote:
    :arrow: Quarz

    I know what I have calculated :wink: and I wrote it well - I wrote (or actually commented) about _resistance_ R = 4287.3? given earlier by col. lucasek (because a 1m steel wire with a diameter of 1.43mm with over 4k? is a bit much ...)

    so for the future AND AND means a B B mean... :D

    greetings
  • #10 3852443
    elek555
    Level 37  
    Some miracles happened to my colleagues higher because steel is harder to conduct, but this is not a reason for it to become a high resistance wire. Following Wikipedia and assuming that all iron has ??10 ^ -7?m, with a cross-section of about 1.6mm? and a length of 1m, the resistance comes out to about 1/16 ?. Of course, you can count it more precisely, but I don't want to.

Topic summary

The discussion centers on calculating the cross-sectional area of a conductor using its diameter, length, and resistance. The formula for the circular cross-section is provided as S = (π * d^2) / 4, where S is the cross-sectional area and d is the diameter. The relationship between resistance (R), resistivity (ρ), length (l), and cross-sectional area (S) is also highlighted with the formula R = ρ * (l / S). A user raises concerns about discrepancies between calculated resistivity values and standard tables, particularly for a steel wire with a diameter of 1.43mm and a resistance of 4287.3 Ohm. The discussion emphasizes the importance of understanding the difference between resistance and resistivity, as well as the material properties affecting conductivity.
Summary generated by the language model.
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