Assuming this previous circuit, it answers the following questions:
If a voltage of 10 volts is applied to the Vi input, respond to the next questions:
Data.- Vd = 0.7v; vz= 4.3v
Note .- Use a decimal when necessary.
1. What current (in mA) flows through DZ1?
2. What is the current (in mA) through the 2K resistor?
3. What current (in mA) flows through DZ2?
4. What should be the minimum value of the input voltage (in volts) so that DZ2 will not
drive?
5. What is the value (in volts) of the voltage Vo?
6. What power (in mW) does the circuit consume or dissipate?
4. What should be the minimum value of the input voltage (in volts) so that DZ2 will not
drive?
5. What is the value (in volts) of the voltage Vo?
6. What power (in mW) does the circuit consume or dissipate?
To analyze the circuit, let's break it down step by step.
1. What current (in mA) flows through DZ1?
Given that Vd = 0.7V and Vz = 4.3V, we can calculate the voltage across the 1K resistor (V_R1) as follows: V_R1 = Vi - Vd - Vz = 10V - 0.7V - 4.3V = 5V
Now, using Ohm's Law, we can find the current through DZ1 (I_DZ1): I_DZ1 = V_R1 / R1 = 5V / 1kΩ = 5mA
2. What is the current (in mA) through the 2K resistor?
Since DZ1 and the 2K resistor are in parallel, the current through the 2K resistor (I_R2) is the same as the current through DZ1: I_R2 = I_DZ1 = 5mA
3. What current (in mA) flows through DZ2?
In this circuit, DZ2 is reverse-biased, so no current will flow through it. Therefore, I_DZ2 = 0mA.
4. What should be the minimum value of the input voltage (in volts) so that DZ2 will not drive?
For DZ2 to not drive, the voltage at the anode (A) of DZ2 should be less than or equal to the voltage at the cathode (K) of DZ2.
V_A = Vd + Vz = 0.7V + 4.3V = 5V
So, the minimum input voltage (Vi_min) to prevent DZ2 from driving is 5V.
5. What is the value (in volts) of the voltage Vo?
Since DZ2 is off, Vo is the same as the voltage across the 2K resistor (V_R2): Vo = V_R2 = I_R2 * R2 = 5mA * 2kΩ = 10V
6. What power (in mW) does the circuit consume or dissipate?
To calculate the total power consumed by the circuit, we need to find the power consumed by each element.
Total power (P_total) is the sum of individual powers: P_total = P_R1 + P_R2 + P_DZ1 + P_D = 25mW + 50mW + 21.5mW + 3.5mW = 100mW
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