5 volt supply from Nokia Battery or 6 Volt battery

Hi , i have a small amplifier which requires USB power to run it, I would like to use a battery which can help me run this instead of using a USB power, please advice?
Thank you

http://pinouts.ws/usb-pinout.html check the link and connect the two wires to vcc and ground connect 4 AA size batteries ...

If the 6 Volts is a solid requirement, then you need an LDO 5 volt regulator that draws as little quiescent current (i.e. current of it's own) as possible. If surface mount is not a problem, then try this (though it's only good to 250ma so it doesn't cover the full USB current range):

* MCP1703-5002E/DB Mouser Part #: 579-MCP1703-5002E/DB

A thru hole possibility is (but it's only good to 100ma):

* LP2950-50LPRE3 Mouser Part #: 595-LP2950-50LPRE3

These are ones that I have used in the past, if you need more current handling capability, then you'll need to search for something else (or perhaps someone else will chime in with a alternative

Okay best of luck

Do you disagree with my comment? It's OK if you do--I'm always open to learn something new.

Thank you Siraj & Steve, i will try this out

Hi Steve, its difficult to get these parts back here so it would be good if could mention a simple way to do this ?

OK Imran,

Put yourself in my place. When you say "here", what the heck do you mean? Where is _here_. Then, after you answer that, someone from where ever 'here' is, will probably need to assist you, since I doubt I will be able to.

First you should get data for your amplifier and read about the manual. Many amplifiers have builtin voltage regulators specially the low voltages since the may be built to be battery supplied.
And as Steve points out you cant get any answears that are better than your questions, the moore specific your question is the better answear!!!!!!!!!!!!!!!
Is the amplifier for sound then u could use just the battery many times is it for measuring something there will be another matter.

Since Imram is proposing to use a 6V battery as the power source, a 5V LDO may not be the optimal choice. A typical LDO like these will have a drop out voltage about 300mV. This means that the circuit will fail if the battery voltage drops by just 700mV, which it is likely to do during the course of a normal discharge and under heavy transient current loads.

I would suggest a SEPIC, buck-boost, or flyback converter such as the "National Semiconductor LM2587-5.0":http://www.ti.com/lit/ds/symlink/lm2587.pdf. These types of DC/DC converters will continue to produce the correct output if the input voltage is above, nearly equal to, or even below the 5V output voltage. It’s a bit more complicated to implement, but the circuit will still work even if the Nokia battery voltage sags during use.

Member of "StrykerTECH":http://www.stryker-tech.com/ Engineering Staff

When I said here, i meant in Amsterdam......