How Can I Isolate the analog voltage

I want to measure voltage with pic microcontroller by this circuit and my question is
1- is this circuit is safe for microcontroller ?
2- how I can to isolate the output of the circuit
 v(an) AN1 to the pin of the microcontroller AN1 ?

 if the circuit safe to microcontroller
I want to protect the microcontroller
I refer to Opto-isolator

this circuit

The circuit may be OK by itself if there are no ground loop problems or hazardous voltages.
An optoisolator by itself is useless if you want a linear response with voltage over a good dynamic range. There are various ways of using optocouplers to overcome this problem, but all the same, bandwidth, linearity, and dynamic range can suffer.
http://electronics.stackexchange.com/question...ectly-proportional-output-galvanically-isolat
https://www.broadcom.com/products/optocoupler...ecific-function/high-linearity-analog/hcnr201

There are other options,
http://www.silabs.com/SupportDocuments/TechnicalDocs/AN614.pdf

Cheers,
Richard

you mean that this circuit is good
I sorry about my many questions
but if lm258 destroyed by high votage or another proplem
a hight voltage may reashed to microcontroller and destroyed
AM I right ?
so i want to using optocouplers to overcome this problem

As far as the circuit being good is concerned, I don't know how you are using it, so I couldn't really say. It is a standard difference amplifier with gain. You can adjust the two input resistors R3 and R6 equally up or down, depending on the voltage you have on the input. R2 and R5 contribute, adjusting them will change the input filter bandwidth as well. So there is plenty of scope to make changes.
Always a possibility that a catastrophy can take place, but if the inputs are not going anywhere near a high voltage, not a problem. If the opamp is destroyed, the worst it likely to do is go to the 12V supply, which may mean reducing R10 a little to make sure the input voltage on the uProcessor is not exceeded. There are all sorts of things that you could do to make it safer, but in the long run, if it is operating under normal conditions I wouldn't worry too much, it will tolerate quite a bit of overloading.
Cheers,
Richard

This circuit is to measure voltage with pic microcontroller by this circuit

You still haven't said what voltage you are trying to measure. With the resistors you have, I would assume in the hundreds of volts.
In that case, I would not advise that you use this method, the PCB layout (creepage and clearance), voltage rating of the resistors, and safety concerns are paramount.
You might be better to use a transformer to step the voltage down, since from the schematic you imply an AC input. If you are using it to measure current in a shunt resisitor, then Hall effect devices are available if the current is high enough, with high breakdown voltages.
Frankly, without knowing what you are using the circuit for, I am not really happy to offer further advice, there are potentially safety issues involved.
Cheers,
Richard

Use isolated DCDC power supply for two different loads,The common solution is using the open-loop push-pull circuit。You can use the self oscillation to the design of a push-pull circuit, or use IC.