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PA443DF Improved Howland Current Pump Output Limited to 2V With ±60V Supply

thphuc 285 2
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  • #1 21868098
    thphuc
    Level 1  
    Posts: 1
    text
    Hi everyone,

    I’m trying to build a constant current source using the PA443DF in an Improved Howland current pump configuration. I’ve previously done this successfully with the OPA454, so I wanted to move to a higher-voltage op-amp. I try to output at least 30-40 mA

    Right now I’m running into a strange issue. The output voltage seems to get stuck at around 2 V amplitude, even though there should be plenty of headroom. I supply the op amp with -60 V Vsupply. It still behaves somewhat like a Howland pump, because when I change the load from 500 Ω to 1 kΩ, the output voltage does change accordingly. However, it never goes beyond roughly 2 V. My input for the op amp are square and sine pulses. I alternatively input pulse in non-inverting pins and inverting pins so that I can have a biphasic pulse.

    This is my first time working with a high-power op amp like the PA443DF, so I suspect I might be misunderstanding something fundamental compared to lower-power parts like the OPA454.

    Any advice or pointers would be greatly appreciated.

    Tektronix oscilloscope screen showing a yellow pulse-like waveform and CH1 measurement readouts on the right.
    This is the sine pulse
    Tektronix TDS 2022C oscilloscope screen showing an almost flat CH1 trace.
    This is the square pulse
    Schematic with PA443DF op-amp, 10 kΩ resistors, and 500–1000 Ω load in a Howland pump setup
    This is how I set up, I think I need to connect Rcl and CC pins to but I don't know how much. I also want to run two op amps of PA443DF at the same time so it can form Improved Howland current.
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  • #3 21868783
    jarek_lnx
    Level 43  
    Posts: 22537
    Help: 4165
    Rate: 6025
    There is a section in the documentation about sizing the Rcl, 10Om should give about 60mA of current limit, this circuit is not precise so you need to give more than the expected output current.

    Without Rcl the circuit will not work
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