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Cable Cross-Section Calculation for 40W Lamps in Parallel: Current 0.35A & 10A per 1mm^2 Rule

adinek 55486 4
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  • #1 3893338
    adinek
    Level 10  
    Hello, I am planning to connect 40W lamps in parallel. I calculated that the current on the power cord would be ~ 0.35A. I once heard that for every 10A I give myself 1mm ^ 2 of the wire. It follows that my wire should only be 0.05mm ^ 2. Is there any mistake in my information?
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  • #2 3893375
    john_t
    Level 29  
    It is not quite like that. It is 11A for 1mm?, but only 25A for 4mm? and 43A for 10mm?. So it is not linear. At low currents, the design cross-section is actually small, but the voltage drop due to the length of the cable and the mechanical strength of the cable must also be taken into account. Therefore, for example, to power motors, it is not recommended to use cables thinner than 2.5mm?, regardless of their low power.
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  • #3 3893613
    grzejab
    Level 23  
    It is more about the fact that, for example, one lamp will make a short circuit, as a result the short-circuit current will not reach a value sufficient for the fuse to trip (in the power network the smallest fuse is 6A) and then a cable with too small cross-section may even heat up to the temperature of ignition of the insulation and it won't be happy anymore.
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  • #4 3893631
    john_t
    Level 29  
    grzejab wrote:
    It is more about the fact that, for example, one lamp will make a short circuit, as a result the short-circuit current will not reach a value sufficient for the fuse to trip (in the power network the smallest fuse is 6A) and then a cable with too small cross-section may even heat up to the temperature of ignition of the insulation and it won't be happy anymore.

    That's right, the fuse protects the line (read the cable) and not the energy receiver against short circuits.
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