Mass Effect on Free Fall: Debunking Weight's Impact on Falling Speed & Time, V = g * t

Hello everyone!
I am writing this post because I have quite a dilemma ... Well, all my friends, family, etc. say that body weight affects the speed and time of falling (free, of course). I am trying to disprove this theory, I even made a bet with a few people , but the formula V = g * t alone does not give anything, and the example of throwing objects into the abyss and measuring the speed after time t, e.g. 3sec, 5sec etc. does not result in: / It is about ideal conditions, so no air resistance, or exactly equal resistance. I am begging you, help me convince them that it is as I say. Oh, of course, I am asking for answers only from those whose information comes from a reliable source, and not from "peasant reason" Thanks in advance to everyone :)

PS You can explain why the hydrogen balloon will go up despite gravity and the CO2 balloon will fall ...
And of course, so as not to be accused of it, I did a test with beer cans one empty second full - they fell the same, but everyone said that the distance was too short ... I'm broken! I'm throwing from the 3rd floor tomorrow

Hello
Free fall:
http://fizzyka.webpark.pl/kinematyka/spadanie/index.htm
Under normal conditions, you will not determine the free fall velocity of the bodies, because you do not have a vacuum.
Free fall only occurs in a vacuum.
For the calculation of the free fall velocity, the body mass is not taken into account, but the accelerations due to Earth, which depends on the height above sea level and latitude.
greetings

Your test with beer cans confirms that the weight has no effect on the "free fall", however when you throw from a greater height there may be a difference in speed but not due to the difference in mass only by friction between the body and air particles.
A balloon filled with CO2 flies down for a simple reason - CO2 is heavier than air, and a hydrogen balloon rises because hydrogen is lighter than air.

Come on thanks guys!
I hope it is enough, although there is never enough opinion
Buddy werpa_29, then a balloon with CO2 and He in a vacuum ... well, they would burst

Soohy_tm wrote:

Come on thanks guys!
I hope it will be enough, although there is never enough opinion
Buddy werpa_29, then a balloon with CO2 and He in a vacuum ... well, they would burst

you're right.
If they are tight and strong enough, they will fall equally.

The weight affects the falling, but only in the air!

Two forces act on a body falling in the air:

- gravity force Fc = m * g
- air resistance force Fo = 0.5 * ? * Cx * A * V * V; [N]

Cx - shape factor

Paweł Es. wrote:

As the speed is steady and does not increase continuously as it would in the absence of air resistance, the fall time will be longer than in a vacuum.

Just when the forces balance each other, according to Newton's First Law of Motion, the body moves with a uniform motion.

Soohy_tm, you must have mistaken the example that the schools usually give that a kilo of feather drops as quickly as a kilo of steel in a vacuum where there is no resistance. Two kilos of feathers in a vacuum will drop faster than a kilo of steel.

And they explain, explain, and somehow they have not internalized this knowledge.

If a kilo of feathers (under ideal conditions, in a vacuum) drops at the same speed as a kilo of steel, then the next kilo of feathers next to the first one also drops so, but if we combine them together (these feathers in 2 kilos), it will accelerate it?

As a reward for such theories, I suggest dropping a kilo of feather on one leg and a kilo of steel on the other.

PS Of course I know you should write a kilo.

A kilogram is a kilogram, no matter if it is feather or steel, it will hurt the same. Unless, according to you, a kilogram of feathers weighs less.
If you drop 2kilo on one leg and a kilogram on the other leg, you will feel the difference.






Ps. kilo - kilo my mistake, I confused it with the prefix 10 ^ 3

Paweł Es. wrote:

The weight affects the falling, but only in the air!

Two forces act on a body falling in the air:

- gravity force Fc = m * g
- air resistance force Fo = 0.5 * ? * Cx * A * V * V; [N]

And I would also consider the buoyancy

staszeks
If you want to be exact, you would have to consider the frictional force and the viscous force and maybe a few others. But let's not go to extremes. I think that the author has already received the answer to his doubts and there is no need to pursue the topic further.

I greet everyone

jjanek

czucz wrote:

A kilogram is a kilogram, no matter if it is feather or steel, it will hurt the same. Unless, according to you, a kilogram of feathers weighs less.
If you drop 2kilo on one leg and a kilogram on the other leg, you will feel the difference.






Ps. kilo - kilo my mistake, I confused it with the prefix 10 ^ 3

you guys have something else wrong, or rather you have forgotten something - about thinking read this topic from the beginning to be sure
and a kilogram is just a thousand grams, "gram" with the prefix "kilo".

Buddy qrdel ... you impressed me :D

Paul Es .:
Disregarding air resistance, possibly considering two balls - one with air and the other with lead with the same sizes:
gravity is the same, air resistance is the same, so according to I will fall equally ...
As for qrdel's statement: A good example, if we consider it correctly, we will come to the conclusion that in the end the bodies will not fall, but float :D

Quote:

czucz:
Soohy_tm, you must have mistaken the example that the schools usually give that a kilo of feather drops as quickly as a kilo of steel in a vacuum where there is no resistance. Two kilos of feathers in a vacuum will drop faster than a kilo of steel.

Has a colleague checked it? because something seems to me that they will fall together after all. Such an example is given in schools (I have heard myself), but certainly not by physics teachers Don't you think there's not enough data to judge it? Oh, and that washes it in the pillow or what? :)

I talked to a friend who is very good at this topic. Below is his statement:

Quote:

... and this comes from the fact that:
F = G * m1 * m2 / r ^ 2
a = F / m1
that is, m1 shortens
m1 - mass of the object
m2 - the mass of the land
r- distance from the center of the earth
G - the constant of gravity
a - acceleration
and so
a = G * m2 / r ^ 2
r ^ 2 - this is obviously r to the power of 2