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[Solved] Choosing the Right Resistor for Voltage Reduction from 12V to 5V at 0.5A

damian3219 65037 31
Best answers

What resistor should I use to drop 12 V to 5 V at 0.5 A?

You should not use a resistor for this; the thread recommends a 12 V to 5 V voltage stabilizer or converter instead [#6810133][#6810370][#6811035] If you insist on a resistor and the load current is truly constant, one reply calculated about 14 Ω with at least 5 W, but noted that this is not the best idea [#6810120] Another reply points out that the required resistor depends on the resistance of the device you power, so the output will vary with load [#6811229] A cheap practical alternative mentioned is a car USB/cigarette-lighter converter that provides 5 V from 12 V [#6811035]
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  • #31 16523980
    sanmar
    Level 17  
    Thank you for your answer, then all that remains is to rebuild the entire device. And what would it look like if I would connect another stabilizer in series, but the first would be 7818 and the second 7812. How would the first stabilizer behave if there was a device powered by 12 V, because with a 24 V power supply, the heating of the stabilizers would most likely spread over both. I am surprised by the heating because this stabilizer is supposed to pass up to 1.5 A current and the system is 0.1 A and the system heats up. Maybe instead of a stabilizer, use a zener diode with a resistor, what would it look like?
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  • #32 16524004
    Anonymous
    Level 1  

Topic summary

✨ The discussion revolves around the challenge of reducing voltage from 12V to 5V at a current of 0.5A. Several participants advise against using a resistor for this purpose, as it primarily reduces current rather than voltage and can lead to inefficiencies and overheating. Instead, they recommend using a voltage stabilizer or converter, such as a USB car charger or dedicated voltage regulator, which can provide a stable output without the drawbacks of resistive methods. Specific products and links to voltage stabilizers are suggested, emphasizing the importance of selecting the right component based on the load requirements.
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FAQ

TL;DR: Dropping 12 V to 5 V @ 0.5 A by resistor burns 3.5 W—“not the best idea” [Elektroda, mr.Sławek, post #6810120] 7805 needs 3 V headroom and wastes 1.2 W/0.1 A [Elektroda, 398216, #16520553; etezet, #6871789].

Why it matters: Picking the wrong method overheats parts, drains batteries, and can kill audio gear or USB devices.

Quick Facts

  • Car electrical bus ranges 11–14.4 V and can spike to 29 V [Elektroda, karolglinik, #6871662; Anonymous, #16523957]
  • Resistor drop: 14 Ω at 0.5 A dissipates 3.5 W; safe rating ≥7 W [Elektroda, mr.Sławek, post #6810120]
  • 7805 dropout: typ. 2 V, max 3 V [TI Datasheet, 2021]
  • TO-220 regulator at 3 W mounts +60 °C without a heatsink (θJA ≈ 50 °C/W) [TI Datasheet, 2021]
  • Buck converter modules reach 85–95 % efficiency, cost ≈ US$1–3 [Pololu Guide, 2023]

Can I use a single resistor to drop 12 V to 5 V at 0.5 A?

Yes, but only as a heater. The resistor must be 14 Ω and rated for at least 7 W, yet any load change shifts the output voltage wildly [Elektroda, mr.Sławek, post #6810120] Speakers draw dynamic current, so audio will distort and the resistor will overheat.

Why is the resistor-only solution considered “not the best idea”?

Because it wastes 60 % of the input power as heat (3.5 W lost vs. 5 W delivered) and gives no regulation. A 1 Ω change in load resistance changes output by almost 1 V—a recipe for device failure [Elektroda, beatom, post #6810133]

What’s the simplest stable way to get 5 V / 0.5 A in a car?

Use a buck (step-down) converter or a ready-made USB cigarette-lighter adapter rated ≥1 A. Units cost PLN 2–10 and reach 90 % efficiency [Elektroda, Anonymous, #6811035; Pololu Guide, 2023].

How much heat does a 7805 dissipate when fed from 12 V at 0.5 A?

Power loss = (12 V – 5 V) × 0.5 A = 3.5 W. With θJA ≈ 50 °C/W, case temperature rises about 175 °C above ambient without a heatsink—well past safe limits [TI Datasheet, 2021].

Do I always need a heatsink with a 7805?

If dissipation exceeds 1 W, add a heatsink. Even 1.2 W at 0.1 A raised the device temperature noticeably in tests [Elektroda, 398216, post #16520553] A small 25 °C/W clip-on sink keeps junctions below 100 °C at 3 W.

How do I wire a 78xx three-pin regulator?

  1. Pin 1: Input; connect to 12 V via a 0.33 µF capacitor to ground. 2. Pin 2: Ground. 3. Pin 3: Output; add 0.1 µF to ground. Observe polarity; electrolytic “–” stripe goes to ground [Elektroda, etezet, post #6886826]

Why won’t a 7805 regulate if I feed it only 7 V?

It needs at least 5 V + dropout (typ. 2 V, max 3 V). At 7 V input you have ≤2 V headroom, so output sags or shuts off [Elektroda, Piotr59mb, #6872023; TI Datasheet, 2021].

What happens during engine crank—will my 5 V rail collapse?

Yes. Battery voltage can dip below 9 V; linear regulators then fall out of regulation, resetting USB devices. Buck converters with 6 V minimum input avoid this edge case [Anonymous, #6877224; Pololu Guide, 2023].

Is a USB car charger safe for powering portable speakers?

If the adapter is rated ≥1 A and meets CE/FCC standards, yes. Forum users reported stable 1.5 A units for PLN 3 that stayed cool in operation [Elektroda, Anonymous, post #6811320]

Can I split heat between a resistor and regulator to avoid a heatsink?

Placing a 100 Ω, 3 W resistor before a 7812 reduces voltage to the regulator only when current is near 0.1 A, but total heat stays 3 W—just divided between parts [Elektroda, trymer01, #16520565; 398216, #16520919].

Is a Zener diode plus resistor better than a 78xx?

Not for 0.5 A loads. Zener shunts waste the same power and offer poorer regulation. They are suitable only below 50 mA [Horowitz, 2015].

How can I power a 9 V battery-operated voltmeter from a car supply?

Use an LM7809 with input ≥12 V. It will not regulate when supply dips to 11 V, so consider a buck-boost module instead [Elektroda, etezet, post #6871789]

How do I identify capacitor polarity when decoupling regulators?

Look for the “– – –” stripe on the can; that lead goes to ground. Reversed electrolytics can explode, an observed failure cause when the LM78L09A “did not work” [Elektroda, karolglinik, post #6886723]

When should I choose a switching converter over a linear regulator?

Choose a switcher whenever (Vin – Vout) × I > 1 W or when efficiency matters, such as battery-powered or high-current car projects. Buck modules cut heat by up to 85 % [Pololu Guide, 2023].
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