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Single phase motor calculation of the current that it draws from the network

apexior 14631 5
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Treść została przetłumaczona polish » english Zobacz oryginalną wersję tematu
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  • #1 16280803
    apexior
    Level 7  
    I have a problem with one task I would be very grateful for help
    1. Calculate the current that the single-phase motor draws from the network with data:
    Pn = 1.5 KW
    Un = 230V
    cosfn = 0.8
    revolutions = 1450 / min
    85% efficiency
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    #2 16280846
    miecho18
    IT specialist  
    And books are where you lost? The formula for power drawn from the network is P = U * I * cos?
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    #3 16280852
    Berend
    Level 17  
    I=P/Un*cosφ*η

    9,59[A].
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  • #4 16280861
    apexior
    Level 7  
    miecho18 wrote:
    And books are where you lost? The formula for power drawn from the network is P = U * I * cos?


    I knew this pattern, but don't I have to consider efficiency and frequency?

    Added after 5 [minutes]:

    Berend wrote:
    I = P / Un * * cos ?

    9.59 [A].


    Thank you for your help, so I don't have to consider these engine revolutions?
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    #5 16280887
    Berend
    Level 17  
    Turnover and a few other things depend on the frequency, which will definitely not be useful to you at this stage.
  • #6 16280904
    apexior
    Level 7  
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