spider_net wrote: Can I ask for help on how to properly calculate this parameter?
The flow of water depends on the power demand.
For radiators, the temperature difference is so-called. delta t = 5, 10, 15 or 20 degrees.
For delta t = 20, accept 23.26W for 1l / h flow.
The smaller the delta, the power for 1l / h decreases proportionally.
This means that if the temperature difference is 2x less (delta t = 10), the power will be halved and will amount to 11.63 watt.
Analyzing this case further, wishing to maintain the same power, for a temperature difference of 10 degrees, the water flow must be 2x larger than for a temperature difference of 20 degrees.
Of course, the radiator's power depends on the size of this radiator.
You need to know for what water temperature you have selected radiators and then you add the heaters' power for these parameters, depending on the delta you divide by the specified power for 1l / h and the flow of 1 / h will come out.
1m3 / h = 1000 liters / h
Considering the average power of radiators, a maximum of several hundred liters per hour is at stake.
Only the flow of water must be correlated with the power of the boiler, in order not to boil water on the boiler, therefore a trial and error method awaits you to reconcile all these dependencies.