Understanding Maximum Load on One Phase: 3-Phase Installation, 32A Protection & 3kW Devices

Hello,
I have been wondering for several days and looking for an answer, but unfortunately I can't find it.
First better picture from the internet:
https://obrazki.elektroda.pl/7795334600_1562157832.png
Just an example (please don't look at the security features in the schematic):
We have a 3-phase installation and protection, e.g. 32A pre-meter.
Maximum power on one phase P = U * I = 230 * 32 = 7360W.
Let's say the stove and dishwasher in the diagram take 3kW each.
And now I do not know if I understand it correctly, because if they take 3kW, then 3kW: 3 (because 3 phases) = 1kW for one phase and times 2, because two devices.
7360-1k-1k = 5360W and here is still the power that I can use on each phase.
My question is: Do I understand it well?

I apologize in advance that it is written this way, but I wanted it to be very legible and understandable.

Devices such as dishwasher or microwave oven are connected to one phase (of course, it does not have to be the same and cannot even be). You need to distribute all devices more or less evenly into each phase. At each phase you have about what you counted (these are rather the maximum possibilities). Loads.

arturdip wrote:

Devices such as dishwasher or microwave oven are connected to one phase (of course, it does not have to be the same and cannot even be) You need to distribute all devices more or less evenly into each phase. At each phase you have about what you counted (these are rather the maximum possibilities) Loads .

I will just add that in this example drawing, which the thread initiator sent, the receivers powered from one phase are on the right. In this drawing, these are sockets and light bulbs.

If you have a three-phase connection with the power supply, e.g. the one on which the power supply has hung the 32A pre-meter protection (which directly results from the power you requested), then using the next 25A protection in the series, you have 25A to use on each phase separately - assuming that you have receivers single-phase. How is it with three-phase receivers - I do not know.

But my point is, this is multiplication:

xDyzio wrote:

We have a 3-phase installation and protection, e.g. 32A pre-meter.
Maximum power on one phase P = U * I = 230 * 32 = 7360W.

This is for each phase independently for single-phase loads. Only, not 32 times, because 32A is the value of the pre-meter protection. Only times what you have in the contract.