bq). So when the car is off, would the ground function still? Or no?
When you say "the ground" I'm not sure what ground you are referring to, BUT, the ultimate answer to your question is, experiment! Because, even if I did know what ground you are referring to, I would probably still say "experiment!", because I don't know how your car is wired.
bq). What I mean is, when the door is closed, and the gray wire functions how it does, if that indirectly is attached to the cigarette ground, would it mess up the cigarette lighter where I would need a diode? Similar to the reasoning behind needing one for the domelight.
That all depends on whether or not the cigarette lighter ground is ever interrupted by anything. I doubt if it is, but you have brought that into question, so I suggest you test it and find out. If it's a solid ground (i.e. an uninterrupted connection to the negative side of the battery) then no worries. Nothing is going to change that (short of some MASSIVE current, and unless your LED lights can be seen from outer space, I doubt that is an issue ;)
bq). As for the relay, the intention was for it to be grounded when the door opened. So it actually functions fine. Its just because of the dimming it clatters. The way the relay is currently set up actually is a lot more intensive then I have described, but it is irrelavent.
You said yourself that it isn't _fine_ because of the chattering. I think you're making it more complicated than it needs to be. But, if it's irrelevant, then I won't go there.
bq). Knowing my absolutely idiotic mistake, how does it sound?
Assuming the cigarette lighter ground is a solid ground, then just use my circuit diagram (reproduced below). Besides, how am I suppose to comment on "how it sounds" when I don't know the nature of your "intensive relay setup"? And, in fact I don't want to know about your setup. If the truth table is correct, then just use my diagram.
bq). Actually I see one with 400 PIV for $.30 more. So that ought to work. As long as PIV=PRV
Yes PIV=PRV. And, yes, that sounds like the correct diode. And I would pay the extra $.30
When you say "the ground" I'm not sure what ground you are referring to, BUT, the ultimate answer to your question is, experiment! Because, even if I did know what ground you are referring to, I would probably still say "experiment!", because I don't know how your car is wired.
bq). What I mean is, when the door is closed, and the gray wire functions how it does, if that indirectly is attached to the cigarette ground, would it mess up the cigarette lighter where I would need a diode? Similar to the reasoning behind needing one for the domelight.
That all depends on whether or not the cigarette lighter ground is ever interrupted by anything. I doubt if it is, but you have brought that into question, so I suggest you test it and find out. If it's a solid ground (i.e. an uninterrupted connection to the negative side of the battery) then no worries. Nothing is going to change that (short of some MASSIVE current, and unless your LED lights can be seen from outer space, I doubt that is an issue ;)
bq). As for the relay, the intention was for it to be grounded when the door opened. So it actually functions fine. Its just because of the dimming it clatters. The way the relay is currently set up actually is a lot more intensive then I have described, but it is irrelavent.
You said yourself that it isn't _fine_ because of the chattering. I think you're making it more complicated than it needs to be. But, if it's irrelevant, then I won't go there.
bq). Knowing my absolutely idiotic mistake, how does it sound?
Assuming the cigarette lighter ground is a solid ground, then just use my circuit diagram (reproduced below). Besides, how am I suppose to comment on "how it sounds" when I don't know the nature of your "intensive relay setup"? And, in fact I don't want to know about your setup. If the truth table is correct, then just use my diagram.
bq). Actually I see one with 400 PIV for $.30 more. So that ought to work. As long as PIV=PRV
Yes PIV=PRV. And, yes, that sounds like the correct diode. And I would pay the extra $.30