Why do you add 1 amp to a short circuit when solving for Rth.
Where does the 1 amp come from when solving for Rth using dc analysis tactics?
the diagram is attached.
I know we begin by finding the Thevenin equivalent with respect to Ro.
This is done by using source transformations.
The you have to use the thevenin source testing method to find Thevenin resistance.
My question is that that when applying the short circuit we assume that it becomes 1 amp.
I have attached the question for convenience. I got the right answer after help from a solutions guide, but I don't understand exactly how to approach the problem. I also feel as if there may be an easier way to do the problem.
