FAQ
TL;DR: A cubic foot of water weighs 64 lb, and “The lifting force is equal to the volume of water displaced.” In an underwater balloon rig, buoyancy comes from compressed air you already paid to compress; without external input, net energy is ≤ 0. [Elektroda, Anonymous, post #21683656]
Why it matters: This FAQ helps inventors assess if a rising-balloon ‘SeaPower’ concept can beat losses or serve as energy storage.
Quick Facts
- Buoyant force equals displaced-water weight minus balloon and air mass; 1 ft³ water ≈ 64 lb. [Elektroda, Anonymous, post #21683656]
- No free energy: compression energy in equals or exceeds energy out at the shaft. [Elektroda, Anonymous, post #21683657]
- Corrected math: 36 ft³ at 18 ATM equals 648 ft³ at 1 ATM, not higher. [Elektroda, Anonymous, post #21683667]
- Practical target cited in thread for storage efficiency is ~85% or more. [Elektroda, Anonymous, post #21683668]
- Offshore depth adds build, maintenance, and transmission cost and complexity. [Elektroda, Anonymous, post #21683666]
Does an underwater rising balloon generator create or store energy?
It converts energy you put into compressing air into buoyant lift, then into mechanical/electrical output. Without external energy input, you cannot get net-positive energy after losses. Use it as storage, not generation. [Elektroda, Anonymous, post #21683657]
How does buoyancy translate to lifting force here?
Each balloon’s upward force equals the weight of displaced water minus the balloon and air weight. Designers often quote 64 lb per cubic foot of water to estimate lift, then subtract system mass. “The lifting force is equal to the volume of water displaced.” [Elektroda, Anonymous, post #21683656]
Where do the claimed “extra” lifting forces come from as balloons rise and expand?
Expansion increases displaced volume and instantaneous lift, but that energy traces back to the compression work done at depth. Summing multiple balloons does not create energy; it partitions the same input with losses. [Elektroda, Anonymous, post #21683657]
What was wrong with the 36 ft³ at 18 ATM expansion example?
At 18 ATM, 36 ft³ of air expands to about 648 ft³ at 1 ATM, setting an upper bound. Intermediate estimates must be lower than 648 ft³, so larger figures overstate lift and energy. [Elektroda, Anonymous, post #21683667]
Is this a perpetual motion machine (PMM)?
No. “Energy cannot be created or destroyed, but only changed from one form into another.” Compression, drag, and conversion losses ensure output is less than input. Any result showing more out than in indicates an error. [Elektroda, Anonymous, post #21683668]
Could I drive the compressor with solar or wind and use the balloons as storage?
Yes, treat the underwater system as energy storage charged by PV or wind. The win hinges on round‑trip efficiency and cost versus batteries, pumped hydro, or other options cited near ~85% benchmarks. [Elektroda, Anonymous, post #21683668]
What losses must I include in an energy balance?
Include compressor efficiency, water drag on balloons and rigging, pulley or gearbox friction, and the weight of contained air. These reduce net shaft output and can flip a design from promising to loss‑making. [Elektroda, Anonymous, post #21683667]
How deep should the system go, and why does depth matter?
Greater depth raises pressure, so air compression work increases while available buoyant expansion grows. One example used 18 ATM at about 594 ft to illustrate scaling, but depth also spikes cost and complexity. [Elektroda, Anonymous, post #21683662]
What makes deep-sea installations hard in practice?
Building, maintaining, and transmitting power offshore is costly. Saltwater corrosion, storms, access logistics, and long cables add OPEX and CAPEX that can erase theoretical gains. Local generation often wins. [Elektroda, Anonymous, post #21683666]
How do I run a quick energy-balance check on this concept?
- Compute compression energy to supply the required air at depth.
- Estimate mechanical work from the buoyant rise, minus drag and drivetrain losses.
- Compare outputs to inputs; if output < input, it cannot self‑power. [Elektroda, Anonymous, post #21683663]
What does “ATM” mean in the thread?
ATM denotes atmospheres of pressure relative to surface atmospheric pressure. For example, 18 ATM means pressure is eighteen times surface level in the example calculations. [Elektroda, Anonymous, post #21683662]
What is a Perpetual Motion Machine (PMM)?
A PMM is a hypothetical machine that outputs more energy than it receives. The thread rejects this as it violates conservation of energy and real‑world losses. [Elektroda, Anonymous, post #21683668]
Could natural seabed gas bubbles power a version of this?
Yes, external bubbles provide an energy source you did not pay to compress. You could harness that flow for generation, though safety and continuity are concerns. [Elektroda, Anonymous, post #21683668]
Who is this approach for, and what problem does it solve?
It targets experimenters exploring mechanical energy storage using buoyancy. The goal is shifting renewable energy across time, not creating energy from nothing. [Elektroda, Anonymous, post #21683657]