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Selecting Cable Cross-Section for Domestic Installations: Power, Frequency, Length & Voltage

misiek118 56423 7
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Treść została przetłumaczona polish » english Zobacz oryginalną wersję tematu
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  • #1 8767710
    misiek118
    Level 12  
    Hello colleagues
    I would like to ask someone to give the formula for the cross-section of the wire due to: the power of the receiver and the "frequency" of its use, length of the wire, supply voltage, losses.
    More precisely, it is about the selection of the cable cross-section in domestic installations.
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  • #2 8767730
    Anonymous
    Anonymous  
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  • #3 8767758
    misiek118
    Level 12  
    Not
    They used to have this formula in high school
    Unfortunately, I can't find these notebooks anywhere :/
    Now I am studying and in my free time I would like to "play" with designing such installations and maybe one day I will deal with it professionally
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  • Helpful post
    #4 8768040
    JohnySpZOO
    Electric installations specialist  
    misiek118 wrote:
    frequency of its use
    Maybe a colleague can explain it to me - I'm a student too and this is the first time I've heard of such a statement.

    Maybe your friend is referring to the following pattern:

    For a 3-phase circuit:
    s=(P*l)/(?*U*?U*cos? ;)
    For a 1-phase circuit:
    s=(3*P*l)/(?*U*?U*cos? ;)
    where:
    s - cable cross-section [mm?]
    P - power [W]
    l - cable length [m]
    ? - conductivity, Cu=57[m/?mm?], Al=34.8[m/?mm?]
    U - voltage [V]
    ?U - allowable voltage drop [V]
    cos? - power factor

    Here are other patterns link

    PS Contrary to appearances, designing such installations is not that easy :)
  • #5 8768107
    misiek118
    Level 12  
    Those are the patterns I'm talking about

    what about "frequency"

    the point is that, for example, on one circuit there are several sockets to which we connect (washing machine, dryer and curling iron), but we do not use all devices at the same time for 24 hours

    but thanks for the pattern anyway

    and if I'm not mistaken the pattern then looks like this
    s=E(P*l*x)/(?*U*?U*cos? ;)

    E - sum
    x - this coefficient ( 0.1 - 1)
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  • #7 8768950
    misiek118
    Level 12  
    That's about it.
    Thank you very much for your help and best regards
  • #8 8769009
    retrofood
    VIP Meritorious for electroda.pl  
    misiek118 wrote:
    Not
    They used to have this formula in high school
    Unfortunately, I can't find these notebooks anywhere :/
    Now I am studying and in my free time I would like to "play" with designing such installations and maybe one day I will deal with it professionally


    And Buddy, why are you posting in the professional section??? The topic is not even very suitable for the section for beginners from the profession.
    But for "beginners" I'm transferring it.
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Topic summary

The discussion revolves around the selection of cable cross-section for domestic electrical installations, focusing on factors such as power, frequency, length, voltage, and losses. A user seeks formulas for calculating the appropriate wire cross-section, referencing both single-phase and three-phase circuits. The formulas provided include variables for power (P), cable length (l), conductivity (?), voltage (U), allowable voltage drop (?U), and power factor (cos?). The conversation also touches on the concept of a coincidence factor to account for multiple devices connected to a single circuit, emphasizing the complexity of designing such installations.
Summary generated by the language model.
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